Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 4)
4.
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
Discussion:
29 comments Page 1 of 3.
Gopi said:
1 decade ago
Kwh = (350*24*24)/1000
= 201.6kWh
= 201.6kWh
Balu said:
1 decade ago
Correct.
Parmjit singh said:
1 decade ago
Hi can you tell me if 540watt and 26 day what ans ?
Rajesh said:
1 decade ago
For 540w
(540*24*26)/1000=336.96kwh
(540*24*26)/1000=336.96kwh
Sush said:
1 decade ago
Gopi is correct.
SANDYACHETHU said:
1 decade ago
1 day = 24 hours,
24 days = ? hours,
(days x 1 day hours) = 24 days hours,
24x24 = 576 hours.
Now: 350x576 = 201600wh,
201600/1000 = 201.6 kwh.
24 days = ? hours,
(days x 1 day hours) = 24 days hours,
24x24 = 576 hours.
Now: 350x576 = 201600wh,
201600/1000 = 201.6 kwh.
Elavendhan said:
1 decade ago
@Sandyachethu answer is perfect
1 Day = 24 Hours
24Day = 24*24
= 576 Hours
Kwh = (3950*576)/1000
= 201.6 kwh
1 Day = 24 Hours
24Day = 24*24
= 576 Hours
Kwh = (3950*576)/1000
= 201.6 kwh
Hirdesh Pal said:
1 decade ago
Gopi you are right & thank you.
Rahul said:
1 decade ago
But who said you that 350w us per hour consumption?
Ravi Purohit said:
1 decade ago
It is Option B because 350 watt X 24 days X 24 hours per that = 201600 watt-hour = 201. 6 kilo watt-hour.
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