# Electrical Engineering - Energy and Power - Discussion

### Discussion :: Energy and Power - General Questions (Q.No.4)

4.

A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?

 [A]. 20.16 kWh [B]. 201.6 kWh [C]. 2.01 kWh [D]. 8.4 kWh

Explanation:

No answer description available for this question.

 Gopi said: (Jan 13, 2011) Kwh = (350*24*24)/1000 = 201.6kWh

 Balu said: (Jan 22, 2011) Correct.

 Parmjit Singh said: (Apr 22, 2011) Hi can you tell me if 540watt and 26 day what ans ?

 Rajesh said: (Jun 1, 2011) For 540w (540*24*26)/1000=336.96kwh

 Sush said: (Aug 31, 2011) Gopi is correct.

 Sandyachethu said: (Nov 15, 2011) 1 day = 24 hours, 24 days = ? hours, (days x 1 day hours) = 24 days hours, 24x24 = 576 hours. Now: 350x576 = 201600wh, 201600/1000 = 201.6 kwh.

 Elavendhan said: (Jan 3, 2012) @Sandyachethu answer is perfect 1 Day = 24 Hours 24Day = 24*24 = 576 Hours Kwh = (3950*576)/1000 = 201.6 kwh

 Hirdesh Pal said: (Mar 21, 2012) Gopi you are right & thank you.

 Rahul said: (Apr 26, 2012) But who said you that 350w us per hour consumption?

 Ravi Purohit said: (Jun 18, 2012) It is Option B because 350 watt X 24 days X 24 hours per that = 201600 watt-hour = 201. 6 kilo watt-hour.

 N Kiran said: (Jun 27, 2012) 350w*24days*24hours = 201.6kw all are says correct answer.

 Tshering said: (Sep 17, 2012) Energy(kWh)= Power(kW) x Time(hrs) Power=350 watt i.e 350/1000= 0.350 kW Time(hr)= 24days, i.e 24x24= 576 hrs Therefore, E= 576x0.350= 201.6 hence energy consumed = 201.6 kWh

 Pramod Shinva said: (Sep 1, 2013) 1 day = 24 hours. 24 days = 576 hours. KW H = P*TIME IN HOURS. = 350*576 (We are used here 350 watts not a kw). = 201600. Watt hours. = 201600/1000. = 201.6 KW H. IS ANSWER.

 Radha said: (Feb 10, 2014) Hello how you have taken 1000? why you divided ?

 Rathi said: (Feb 10, 2014) @Radha. Because 1kW = 1000 W. So 201600 Watt hours is equal to 201.6 kWh.

 Noor Nawaz said: (Jul 6, 2015) 350*24 days*24 hours/1000 for conversion into kilos.

 Messuli said: (Apr 2, 2016) Help please, where do we obtain 1000 from.

 Chavitina Ramakrishna said: (Aug 2, 2016) @Messuli. In the 'KILO watt-hour' asked, that is why we divided with 1000 in the calculation.

 Mukeshbhai Ramanbhai Ganvit said: (Oct 25, 2016) An electrical iron drawing 9 A from 120 V Supply main is operated for 20 minutes, the energy consumed is?

 Sham said: (Jan 19, 2017) Thank you @Pramod Shinva.

 Padma said: (May 12, 2017) Yes, you both are correct @Gopi and @Rajesh.

 Abhi said: (Jul 5, 2017) P=9*120=1080WATT....... FOR UNITY pf. FOR 20 MIN, E=(1080*20)/1000 =21.6kwh.

 Mahantesh said: (Sep 18, 2017) 201.6kwh is correct.

 Sstyam said: (Mar 8, 2018) You are correct, Thanks @Gopi.

 Pravin Gaikwad said: (Aug 27, 2018) Here, it is (use in watt * total hours)/1000.

 Raza said: (Oct 30, 2018) Total kWH = power * time. = 350 (watt) *24 (hour) *24 (days), = 201600 watt hour, = 201.6 kWH.

 Ali Baba said: (Jul 16, 2019) Thanks to all for explaining the answer.