### Discussion :: Energy and Power - General Questions (Q.No.4)

Gopi said: (Jan 13, 2011) | |

Kwh = (350*24*24)/1000 = 201.6kWh |

Balu said: (Jan 22, 2011) | |

Correct. |

Parmjit Singh said: (Apr 22, 2011) | |

Hi can you tell me if 540watt and 26 day what ans ? |

Rajesh said: (Jun 1, 2011) | |

For 540w (540*24*26)/1000=336.96kwh |

Sush said: (Aug 31, 2011) | |

Gopi is correct. |

Sandyachethu said: (Nov 15, 2011) | |

1 day = 24 hours, 24 days = ? hours, (days x 1 day hours) = 24 days hours, 24x24 = 576 hours. Now: 350x576 = 201600wh, 201600/1000 = 201.6 kwh. |

Elavendhan said: (Jan 3, 2012) | |

@Sandyachethu answer is perfect 1 Day = 24 Hours 24Day = 24*24 = 576 Hours Kwh = (3950*576)/1000 = 201.6 kwh |

Hirdesh Pal said: (Mar 21, 2012) | |

Gopi you are right & thank you. |

Rahul said: (Apr 26, 2012) | |

But who said you that 350w us per hour consumption? |

Ravi Purohit said: (Jun 18, 2012) | |

It is Option B because 350 watt X 24 days X 24 hours per that = 201600 watt-hour = 201. 6 kilo watt-hour. |

N Kiran said: (Jun 27, 2012) | |

350w*24days*24hours = 201.6kw all are says correct answer. |

Tshering said: (Sep 17, 2012) | |

Energy(kWh)= Power(kW) x Time(hrs) Power=350 watt i.e 350/1000= 0.350 kW Time(hr)= 24days, i.e 24x24= 576 hrs Therefore, E= 576x0.350= 201.6 hence energy consumed = 201.6 kWh |

Pramod Shinva said: (Sep 1, 2013) | |

1 day = 24 hours. 24 days = 576 hours. KW H = P*TIME IN HOURS. = 350*576 (We are used here 350 watts not a kw). = 201600. Watt hours. = 201600/1000. = 201.6 KW H. IS ANSWER. |

Radha said: (Feb 10, 2014) | |

Hello how you have taken 1000? why you divided ? |

Rathi said: (Feb 10, 2014) | |

@Radha. Because 1kW = 1000 W. So 201600 Watt hours is equal to 201.6 kWh. |

Noor Nawaz said: (Jul 6, 2015) | |

350*24 days*24 hours/1000 for conversion into kilos. |

Messuli said: (Apr 2, 2016) | |

Help please, where do we obtain 1000 from. |

Chavitina Ramakrishna said: (Aug 2, 2016) | |

@Messuli. In the 'KILO watt-hour' asked, that is why we divided with 1000 in the calculation. |

Mukeshbhai Ramanbhai Ganvit said: (Oct 25, 2016) | |

An electrical iron drawing 9 A from 120 V Supply main is operated for 20 minutes, the energy consumed is? |

Sham said: (Jan 19, 2017) | |

Thank you @Pramod Shinva. |

Padma said: (May 12, 2017) | |

Yes, you both are correct @Gopi and @Rajesh. |

Abhi said: (Jul 5, 2017) | |

P=9*120=1080WATT....... FOR UNITY pf. FOR 20 MIN, E=(1080*20)/1000 =21.6kwh. |

Mahantesh said: (Sep 18, 2017) | |

201.6kwh is correct. |

Sstyam said: (Mar 8, 2018) | |

You are correct, Thanks @Gopi. |

Pravin Gaikwad said: (Aug 27, 2018) | |

Here, it is (use in watt * total hours)/1000. |

Raza said: (Oct 30, 2018) | |

Total kWH = power * time. = 350 (watt) *24 (hour) *24 (days), = 201600 watt hour, = 201.6 kWH. |

Ali Baba said: (Jul 16, 2019) | |

Thanks to all for explaining the answer. |

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