Electrical Engineering - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 1)
1.
A 10 F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is
2.43 F
4.86 F
100 F
152 F
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Amar kailas randhe said:   1 decade ago
While connecting capacitors in parallel we will add them to get right value.

i.e., 10+20+22+100 and which is equal to 152 microfarad.

Bala said:   1 decade ago
It is opposite to that of resistance i.e.

In resistors we add them when connected in series.

Whereas in capacitors we add them when connected in parallel.

PRAMOD SHINVA said:   1 decade ago
CT = C1+C2+C3+C4.

= 10+20+22+100.

= 152 MICRO FARAD.

ANSWER IS D.

Parmanand said:   1 decade ago
Right answer is 152 because in parallel capacitance circuit. Addition of capacitance value.

Dasi vinodh said:   1 decade ago
Capacitors series and parallel combination is opposite to the resistors series and parallel connection hence total capacitance in parallel is equal to the sum of all capacitances. i.e C = C1+C2+C3+C4+...+Cn.

MONUVARSHNEY said:   1 decade ago
Ceq = C1+C2+C3+C4.

Ceq = 10+20+22+100 = 152.

Vikash Yaduvanshi said:   1 decade ago
C = C1+C2+C3+C4....+Cn.

Prabas said:   1 decade ago
10+20+22+100=152 why because capacitors series.

Mahalaxmi hiremath said:   1 decade ago
C = c1+c2+c3 = 152.

Rupak sahu said:   1 decade ago
Each capacitance are add so 152 micro Faraday.


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