Civil Engineering - Water Supply Engineering - Discussion

Discussion Forum : Water Supply Engineering - Section 3 (Q.No. 29)
29.
The ratio of maximum hourly consumption and average hourly consumption of the maximum day, is
1.2
1.5
1.8
2.4
2.7
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 1 of 4.

James said:   2 years ago
@All.

Here;

It's a given statement from a table to remember as it is,

Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,

= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.

So, E is the correct answer.
(4)

Sayantan said:   2 years ago
I too agree, B is the correct answer.
(2)

Laltu said:   3 years ago
If it was annual Average hourly demand then the answer is 2.7. And now 1.5.
(1)

Namrata giri said:   3 years ago
B is the correct answer.
(1)

Rakesh said:   3 years ago
Average means not maximum.

So, factor use higher 2.7.
(1)

Arsalan said:   3 years ago
Given answer is correct.

As 1.5 is max hourly consumption factor and 1.8 is the max daily consumption factor.

In question, it is asked that ratio of maximum hourly consumption and average hourly consumption of the maximum day. So we have to apply both factors to avg daily consumption.

1.5-1.8 = 2.7.
(1)

ONKAR said:   6 years ago
Given answer is correct. I agree with it.
(1)

Hassan said:   6 years ago
According to Good rich formula :

P=180 x t^-0.1.

Where t=time in days
P is in per cent.

For maximum hourly consumption t= 1/24 days,
So, P= 180 x (1/24),
= 247%.

Hence the ratio should be 2.4 and not 2.7.
Thus the correct option should be (D).

Naveen said:   3 years ago
I think B should be the correct answer.

Sandeep kshetri said:   4 years ago
C is the correct answer. Maximum daily consumption=1.8 * average consumption.


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