Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 3 (Q.No. 29)
29.
The ratio of maximum hourly consumption and average hourly consumption of the maximum day, is
Discussion:
31 comments Page 1 of 4.
James said:
2 years ago
@All.
Here;
It's a given statement from a table to remember as it is,
Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
So, E is the correct answer.
Here;
It's a given statement from a table to remember as it is,
Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
So, E is the correct answer.
(4)
Priya said:
7 years ago
Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
Arsalan said:
3 years ago
Given answer is correct.
As 1.5 is max hourly consumption factor and 1.8 is the max daily consumption factor.
In question, it is asked that ratio of maximum hourly consumption and average hourly consumption of the maximum day. So we have to apply both factors to avg daily consumption.
1.5-1.8 = 2.7.
As 1.5 is max hourly consumption factor and 1.8 is the max daily consumption factor.
In question, it is asked that ratio of maximum hourly consumption and average hourly consumption of the maximum day. So we have to apply both factors to avg daily consumption.
1.5-1.8 = 2.7.
(1)
Hassan said:
6 years ago
According to Good rich formula :
P=180 x t^-0.1.
Where t=time in days
P is in per cent.
For maximum hourly consumption t= 1/24 days,
So, P= 180 x (1/24),
= 247%.
Hence the ratio should be 2.4 and not 2.7.
Thus the correct option should be (D).
P=180 x t^-0.1.
Where t=time in days
P is in per cent.
For maximum hourly consumption t= 1/24 days,
So, P= 180 x (1/24),
= 247%.
Hence the ratio should be 2.4 and not 2.7.
Thus the correct option should be (D).
Dheeraj kataria said:
5 years ago
The question is totally wrong... How the ratio come 2.7?
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Paras said:
9 years ago
It's option B.
Max. Hourly consumption is 2.7 times the average annual hourly consumption. And 1.5 times Avg hourly consumption on the day of maximum use.
Max. Hourly consumption is 2.7 times the average annual hourly consumption. And 1.5 times Avg hourly consumption on the day of maximum use.
MJM Gcek said:
4 years ago
B is correct and if the question would be for average hourly consumption for average daily instead of max daily then option E should be valid.
Satyaki said:
5 years ago
The ratio of max. hourly consumption =( 2.7 LPCD /24).
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
Sandeep kshetri said:
4 years ago
C is the correct answer. Maximum daily consumption=1.8 * average consumption.
Laltu said:
3 years ago
If it was annual Average hourly demand then the answer is 2.7. And now 1.5.
(1)
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