Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 3 (Q.No. 29)
29.
The ratio of maximum hourly consumption and average hourly consumption of the maximum day, is
Discussion:
31 comments Page 2 of 4.
Tinsae said:
4 years ago
Agree, the correct answer is option E.
MJM Gcek said:
4 years ago
B is correct and if the question would be for average hourly consumption for average daily instead of max daily then option E should be valid.
Suraj kumar said:
4 years ago
Thanks for explaining @Priya.
ATUL KOUSHAL said:
5 years ago
B is correct. I too agree.
Dheeraj kataria said:
5 years ago
The question is totally wrong... How the ratio come 2.7?
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Satyaki said:
5 years ago
The ratio of max. hourly consumption =( 2.7 LPCD /24).
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
Dipu said:
6 years ago
B will be the right answer.
Paras said:
9 years ago
It's option B.
Max. Hourly consumption is 2.7 times the average annual hourly consumption. And 1.5 times Avg hourly consumption on the day of maximum use.
Max. Hourly consumption is 2.7 times the average annual hourly consumption. And 1.5 times Avg hourly consumption on the day of maximum use.
Kartik said:
7 years ago
Thank you @Priya.
Priya said:
7 years ago
Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
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