Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 30)
30.
The degree of indeterminacy of the frame in the given figure, is
Discussion:
38 comments Page 3 of 4.
Anomie said:
7 years ago
m = 10 j= 6 r = 5.
10 -2 * 6 + 5.
3.
10 -2 * 6 + 5.
3.
Nyokir said:
6 years ago
Correct answer is 1.
ii= m-2j+3,
ie=r-R.
Total indeterminacy= ii+ie.
Where,
m=10, j=6, r=3, R=3.
ii= m-2j+3,
ie=r-R.
Total indeterminacy= ii+ie.
Where,
m=10, j=6, r=3, R=3.
Karn chaurasiya said:
6 years ago
Ds= m +r --2j ,m= 10,r= 3( hinge 2 roller 1 so total r=3), j = 6
Ds= m+r -2j= 10 +3 -2 * 6 = 1.
So I think the answer is 1 and if we take j= 5 then answer ds= 10+ 3 - 5 * 2 = 3.
Ds= m+r -2j= 10 +3 -2 * 6 = 1.
So I think the answer is 1 and if we take j= 5 then answer ds= 10+ 3 - 5 * 2 = 3.
Ajay said:
6 years ago
First panel carries 1 extra member which disturbs the triangular behaviour of the frame. Whereas the 2nd panel has perfect triangular behaviour.
So, the static indeterminacy is 1.
So, the static indeterminacy is 1.
Anuraag Athreya said:
6 years ago
The hint is given in the question that BC should be considered as one member. So only 9 members.
5 Joints and 3 reactions...applying m+r-2j the answer is 2.
5 Joints and 3 reactions...applying m+r-2j the answer is 2.
Anuraag Athreya said:
6 years ago
Considering a joint is one where only ends of the members are joining.
Saqib khattak said:
6 years ago
Anyone explain the correct method for the answer.
Manimegalai said:
6 years ago
How did you tell member=10? Joint=6, reaction=3, please explain.
Alagarbrindha said:
6 years ago
m= 12, r= 3, j= 7.
Ds= m+r-2j.
Hence Ds= 12+3-7(2) = 15-14 = 1.
Ds= m+r-2j.
Hence Ds= 12+3-7(2) = 15-14 = 1.
Nihar said:
6 years ago
How to find r here?
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