Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 30)
30.
The degree of indeterminacy of the frame in the given figure, is
Discussion:
38 comments Page 1 of 4.
Dhritiranjan Nath said:
2 years ago
If you consider the joint then you have to consider the members related to that joint.
If we consider the member as 12 then we have to consider the diagonal cross joint too.
From that concept. Indeterminacy= 12+3-2x7= 1.
If we consider the m as 10, then J=6, so indeterminacy=10+3-2x6=1, so the correct answer will be 1.
If we consider the member as 12 then we have to consider the diagonal cross joint too.
From that concept. Indeterminacy= 12+3-2x7= 1.
If we consider the m as 10, then J=6, so indeterminacy=10+3-2x6=1, so the correct answer will be 1.
(1)
Bikash Bhattrai said:
4 years ago
For pin-jointed frame Degree of indeterminacy = m+r-2j here m= 12 are =3 & j = 6 so the answer will be 3 do not confuse for joint as seven by counting diagonal cross joint others are well clear there is a roller and hinge support so the reaction is 3.
(1)
Steve said:
7 years ago
This is an example of a pin jointed frame and as such, the formula should be D=n+r-2j.
where D= degree of indeterminacy.
n= number of member= 10,
r= number of reaction=3,
j= number of joints=5.
Hence, we have D=10+3-2(5)= 3.
where D= degree of indeterminacy.
n= number of member= 10,
r= number of reaction=3,
j= number of joints=5.
Hence, we have D=10+3-2(5)= 3.
Prafulla said:
5 years ago
Dse = m-2 * (j-4)+3,m = 2.
m - no. Of members require to form an extra joint, (j-4) joints to form an extra joint j=5 substitute in above eqn we get dse = 3.
Dsi = r-3 = 3-3=0,
Ds = dse+dsi = 0+3 = 3.
m - no. Of members require to form an extra joint, (j-4) joints to form an extra joint j=5 substitute in above eqn we get dse = 3.
Dsi = r-3 = 3-3=0,
Ds = dse+dsi = 0+3 = 3.
Karn chaurasiya said:
6 years ago
Ds= m +r --2j ,m= 10,r= 3( hinge 2 roller 1 so total r=3), j = 6
Ds= m+r -2j= 10 +3 -2 * 6 = 1.
So I think the answer is 1 and if we take j= 5 then answer ds= 10+ 3 - 5 * 2 = 3.
Ds= m+r -2j= 10 +3 -2 * 6 = 1.
So I think the answer is 1 and if we take j= 5 then answer ds= 10+ 3 - 5 * 2 = 3.
Ajay said:
6 years ago
First panel carries 1 extra member which disturbs the triangular behaviour of the frame. Whereas the 2nd panel has perfect triangular behaviour.
So, the static indeterminacy is 1.
So, the static indeterminacy is 1.
Anuraag Athreya said:
6 years ago
The hint is given in the question that BC should be considered as one member. So only 9 members.
5 Joints and 3 reactions...applying m+r-2j the answer is 2.
5 Joints and 3 reactions...applying m+r-2j the answer is 2.
Ankit said:
8 years ago
Why you calculate r =5?
If here joint take 6 then member 10. The answer is 1. If take joint 7 then member 12. The answer is 1.
So the answer is always 1.
If here joint take 6 then member 10. The answer is 1. If take joint 7 then member 12. The answer is 1.
So the answer is always 1.
Habiba said:
3 years ago
Point C is also considered hinged so the total of reactions is 5.
R is 5,
M is 12,
J is 7.
And DETERminacy is 12+5-(14)=3.
R is 5,
M is 12,
J is 7.
And DETERminacy is 12+5-(14)=3.
Pankaj kanwar said:
9 years ago
I think the answer should be 1.
Because here m =10, r=3 and joints are 6.
Therefore m+r-2j.
10+3-(2 * 6) = 1.
Because here m =10, r=3 and joints are 6.
Therefore m+r-2j.
10+3-(2 * 6) = 1.
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