# Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 2 (Q.No. 30)

30.

The degree of indeterminacy of the frame in the given figure, is

Discussion:

38 comments Page 1 of 4.
Dhritiranjan Nath said:
1 year ago

If you consider the joint then you have to consider the members related to that joint.

If we consider the member as 12 then we have to consider the diagonal cross joint too.

From that concept. Indeterminacy= 12+3-2x7= 1.

If we consider the m as 10, then J=6, so indeterminacy=10+3-2x6=1, so the correct answer will be 1.

If we consider the member as 12 then we have to consider the diagonal cross joint too.

From that concept. Indeterminacy= 12+3-2x7= 1.

If we consider the m as 10, then J=6, so indeterminacy=10+3-2x6=1, so the correct answer will be 1.

(1)

Habiba said:
2 years ago

Point C is also considered hinged so the total of reactions is 5.

R is 5,

M is 12,

J is 7.

And DETERminacy is 12+5-(14)=3.

R is 5,

M is 12,

J is 7.

And DETERminacy is 12+5-(14)=3.

Anon said:
3 years ago

@Bikash Bhattrai.

By your logic, m=10, so the answer is 1.

By your logic, m=10, so the answer is 1.

Ananya said:
3 years ago

Answer should be 2.

m= 12, j=5, r=3.

m= 12, j=5, r=3.

Bikash Bhattrai said:
3 years ago

For pin-jointed frame Degree of indeterminacy = m+r-2j here m= 12 are =3 & j = 6 so the answer will be 3 do not confuse for joint as seven by counting diagonal cross joint others are well clear there is a roller and hinge support so the reaction is 3.

Bhargab said:
4 years ago

The right Answer is 1.

(1)

Prafulla said:
4 years ago

Dse = m-2 * (j-4)+3,m = 2.

m - no. Of members require to form an extra joint, (j-4) joints to form an extra joint j=5 substitute in above eqn we get dse = 3.

Dsi = r-3 = 3-3=0,

Ds = dse+dsi = 0+3 = 3.

m - no. Of members require to form an extra joint, (j-4) joints to form an extra joint j=5 substitute in above eqn we get dse = 3.

Dsi = r-3 = 3-3=0,

Ds = dse+dsi = 0+3 = 3.

Yasir said:
4 years ago

M+r-2j.

Member=m=9,

Joint=j=5,

Reaction=r=3,

=9+3-2(5)=12-10=2.

Member=m=9,

Joint=j=5,

Reaction=r=3,

=9+3-2(5)=12-10=2.

Nihar said:
4 years ago

How to find r here?

Alagarbrindha said:
4 years ago

m= 12, r= 3, j= 7.

Ds= m+r-2j.

Hence Ds= 12+3-7(2) = 15-14 = 1.

Ds= m+r-2j.

Hence Ds= 12+3-7(2) = 15-14 = 1.

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