Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 1 of 3.
Bikash kabiraj said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
Inayat Ullah Kakar said:
9 months ago
Formula:
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
(4)
Maxwell said:
6 years ago
Please anyone solve this, If the modulus of rigidity is given as 42MN/mm square and the modulus of elasticity is 200 KN/mm square, what will be an acceptable value for bulk modulus if the material has a cuboid configuration?
(2)
Mujru said:
9 years ago
The equation related to bulk modulus and modulus of rigidity is;
E = 2n(1+u).
E = bulk modulus,
n= modulus of rigidity,
u = possion raito.
So,
u = E/2n -1.
= 200/(80 * 2) - 1.
= 0.25.
E = 2n(1+u).
E = bulk modulus,
n= modulus of rigidity,
u = possion raito.
So,
u = E/2n -1.
= 200/(80 * 2) - 1.
= 0.25.
Chakradhar padhan said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].e = 3k(1-2/m)=2c(1+1/m)
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
PIYUSH SINGH said:
1 decade ago
Young modulus = E.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Kowsalya said:
4 years ago
E = 200*10^9N/m^2.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
(5)
Abigail said:
9 years ago
I tried d formulae for the relationship between bulk modulus and modulus of rigidity but it's not giving me the right answer.
Can anyone help me?
Can anyone help me?
Rathi said:
1 decade ago
Relation between young's modulus(E), Rigidity modulus(G) and Poisson's ratio(u).
E = 2G(1+u).
u = E/2G - 1.
= 200/2*80 - 1.
u = 0.25.
E = 2G(1+u).
u = E/2G - 1.
= 200/2*80 - 1.
u = 0.25.
(1)
Akshata said:
7 years ago
1st find Youngs Modulus (E) using E= (9KG)/(G+3K) where K=bulk modulus & G= modulus of rigidity then E=2G (1+u) where u= Poisson's ratio.
(1)
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