Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 2 of 3.
Kk bhal said:
6 years ago
The answer is supposed to be 0.4.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
Abhay said:
10 years ago
Young's modulus E = 2G(1 + μ) where, G = Modulus of rigidity.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
Vikas Kumar said:
1 decade ago
Formula of poisson ratio = (E-2G)/2G.
Where E = Young's modulus.
G = Modulus of Rigidity.
Now U = (200-2*80)/2*80 = 0.25.
Where E = Young's modulus.
G = Modulus of Rigidity.
Now U = (200-2*80)/2*80 = 0.25.
Gondelamahesh said:
8 years ago
If the modulus of rigidity is 80 kn/mm square and bulk modulus 140 kn/mm square position ratio is what anyone explain it?
Shruti said:
8 years ago
E = 2G( 1+U),
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
(1)
Ammulu said:
9 years ago
E = 2g(1 + u),
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.
Susmita said:
1 decade ago
We know that C = mE/2 (m+1).
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
Viru kapoor said:
7 years ago
E=2G(1+U).
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
(1)
Mayuri said:
1 decade ago
E = 2G (1-1/m).
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
Nitin ingole said:
1 decade ago
Answer should be 0.25 Poisson's ration = ( E-2G )/2G = (200-2x80)/2*80 = 0.25.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers