Civil Engineering - Strength of Materials - Discussion

28. 

For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is

[A]. 0.15
[B]. 0.20
[C]. 0.25
[D]. 0.30
[E]. 0.40

Answer: Option C

Explanation:

No answer description available for this question.

Nitin Ingole said: (Sep 26, 2013)  
Answer should be 0.25 Poisson's ration = ( E-2G )/2G = (200-2x80)/2*80 = 0.25.

Rathi said: (Sep 28, 2013)  
Relation between young's modulus(E), Rigidity modulus(G) and Poisson's ratio(u).

E = 2G(1+u).

u = E/2G - 1.

= 200/2*80 - 1.

u = 0.25.

Manasa Sundaram said: (Mar 23, 2014)  
c = mE/2(m+1).

1+(1/m) = (2*10^5)/(2*(8*10^4)).

1+u = 1.25.

u = 0.25.

Vikas Kumar said: (May 11, 2014)  
Formula of poisson ratio = (E-2G)/2G.

Where E = Young's modulus.
G = Modulus of Rigidity.

Now U = (200-2*80)/2*80 = 0.25.

Mayuri said: (Dec 31, 2014)  
E = 2G (1-1/m).
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.

Piyush Singh said: (Feb 28, 2015)  
Young modulus = E.
Modulus of Rigidity = G.
Poisson's Ratio = U.

Formula => E = 2G (1-u).

Therefore:

A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.

Susmita said: (Jul 30, 2015)  
We know that C = mE/2 (m+1).

Where C = 80GN/m2.

E = 200GN/m2.

1/m = Poisson's ratio = 0.25.

Abhay said: (Feb 2, 2016)  
Young's modulus E = 2G(1 + μ) where, G = Modulus of rigidity.

=> μ = E/2G - 1.

=> 200/(2*80) - 1.

= 1.25 - 1.

μ = 0.25.

Krishna said: (May 12, 2016)  
You are correct @Rathi.

E = 2G(1+mu)
then u = 0.25.

Mujru said: (Aug 11, 2016)  
The equation related to bulk modulus and modulus of rigidity is;

E = 2n(1+u).
E = bulk modulus,
n= modulus of rigidity,
u = possion raito.

So,
u = E/2n -1.
= 200/(80 * 2) - 1.
= 0.25.

Ammulu said: (Dec 28, 2016)  
E = 2g(1 + u),
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.

Abigail said: (Feb 23, 2017)  
I tried d formulae for the relationship between bulk modulus and modulus of rigidity but it's not giving me the right answer.

Can anyone help me?

Anusha Reddy said: (May 9, 2017)  
Good explanation @Ammulu.

Bikash Kabiraj said: (May 17, 2017)  
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.

Gondelamahesh said: (Jun 9, 2017)  
If the modulus of rigidity is 80 kn/mm square and bulk modulus 140 kn/mm square position ratio is what anyone explain it?

Shruti said: (Jul 26, 2017)  
E = 2G( 1+U),
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.

Chakradhar Padhan said: (Aug 9, 2017)  
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].e = 3k(1-2/m)=2c(1+1/m)
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.

Pradip Behera said: (Feb 5, 2018)  
Here, E=2G(1+u)=3K(1-2u)=9KG/(3K+G).

Akshata said: (Jul 11, 2018)  
1st find Youngs Modulus (E) using E= (9KG)/(G+3K) where K=bulk modulus & G= modulus of rigidity then E=2G (1+u) where u= Poisson's ratio.

Viru Kapoor said: (Jul 23, 2018)  
E=2G(1+U).
Given E=200.
G=80.

200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.

Kk Bhal said: (Apr 16, 2019)  
The answer is supposed to be 0.4.

C = (mE)/2(m+1).

Relationship between Young's modulus of elasticity and Rigid modules.

Ref: RS Khurmi.

Maxwell said: (May 12, 2019)  
Please anyone solve this, If the modulus of rigidity is given as 42MN/mm square and the modulus of elasticity is 200 KN/mm square, what will be an acceptable value for bulk modulus if the material has a cuboid configuration?

Kowsalya said: (Jun 24, 2021)  
E = 200*10^9N/m^2.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).

(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.

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