Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 1 of 3.
Inayat Ullah Kakar said:
9 months ago
Formula:
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
(4)
Kowsalya said:
4 years ago
E = 200*10^9N/m^2.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
(5)
Maxwell said:
6 years ago
Please anyone solve this, If the modulus of rigidity is given as 42MN/mm square and the modulus of elasticity is 200 KN/mm square, what will be an acceptable value for bulk modulus if the material has a cuboid configuration?
(2)
Kk bhal said:
6 years ago
The answer is supposed to be 0.4.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
Viru kapoor said:
7 years ago
E=2G(1+U).
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
(1)
Akshata said:
7 years ago
1st find Youngs Modulus (E) using E= (9KG)/(G+3K) where K=bulk modulus & G= modulus of rigidity then E=2G (1+u) where u= Poisson's ratio.
(1)
Pradip behera said:
8 years ago
Here, E=2G(1+u)=3K(1-2u)=9KG/(3K+G).
Chakradhar padhan said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].e = 3k(1-2/m)=2c(1+1/m)
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
Shruti said:
8 years ago
E = 2G( 1+U),
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
(1)
Gondelamahesh said:
8 years ago
If the modulus of rigidity is 80 kn/mm square and bulk modulus 140 kn/mm square position ratio is what anyone explain it?
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