Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 1 of 3.
Kowsalya said:
4 years ago
E = 200*10^9N/m^2.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
G = 80*10^9N/m^2.
U=?
E=2G(1+U).
(200 * 10^9)/(2 * 80 * 10^9) = (1+U),
100/80 = 1+U,
(10/8)-1 = U,
(5/4)-1 = U,
(5-4)/4 = U.
1/4 = U==>U = 0.25.
(5)
Inayat Ullah Kakar said:
9 months ago
Formula:
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
C = mE/2(m+1)
By rearrannging;
1/m= (E/2C)-1.
1/m=(200/2×80)-1.
1/m= 0.25.
So, The value of Poisson's ratio is value is equal to1/m = 0.25.
So, the given answer is correct because we use the passion ratio value by 1/m.
(4)
Maxwell said:
6 years ago
Please anyone solve this, If the modulus of rigidity is given as 42MN/mm square and the modulus of elasticity is 200 KN/mm square, what will be an acceptable value for bulk modulus if the material has a cuboid configuration?
(2)
Rathi said:
1 decade ago
Relation between young's modulus(E), Rigidity modulus(G) and Poisson's ratio(u).
E = 2G(1+u).
u = E/2G - 1.
= 200/2*80 - 1.
u = 0.25.
E = 2G(1+u).
u = E/2G - 1.
= 200/2*80 - 1.
u = 0.25.
(1)
Viru kapoor said:
7 years ago
E=2G(1+U).
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
Given E=200.
G=80.
200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
(1)
Akshata said:
7 years ago
1st find Youngs Modulus (E) using E= (9KG)/(G+3K) where K=bulk modulus & G= modulus of rigidity then E=2G (1+u) where u= Poisson's ratio.
(1)
Shruti said:
8 years ago
E = 2G( 1+U),
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
(1)
Susmita said:
1 decade ago
We know that C = mE/2 (m+1).
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
Nitin ingole said:
1 decade ago
Answer should be 0.25 Poisson's ration = ( E-2G )/2G = (200-2x80)/2*80 = 0.25.
Manasa Sundaram said:
1 decade ago
c = mE/2(m+1).
1+(1/m) = (2*10^5)/(2*(8*10^4)).
1+u = 1.25.
u = 0.25.
1+(1/m) = (2*10^5)/(2*(8*10^4)).
1+u = 1.25.
u = 0.25.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers