Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 2 of 3.
Vikas Kumar said:
1 decade ago
Formula of poisson ratio = (E-2G)/2G.
Where E = Young's modulus.
G = Modulus of Rigidity.
Now U = (200-2*80)/2*80 = 0.25.
Where E = Young's modulus.
G = Modulus of Rigidity.
Now U = (200-2*80)/2*80 = 0.25.
Kk bhal said:
6 years ago
The answer is supposed to be 0.4.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
C = (mE)/2(m+1).
Relationship between Young's modulus of elasticity and Rigid modules.
Ref: RS Khurmi.
Mayuri said:
1 decade ago
E = 2G (1-1/m).
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
PIYUSH SINGH said:
1 decade ago
Young modulus = E.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Pradip behera said:
8 years ago
Here, E=2G(1+u)=3K(1-2u)=9KG/(3K+G).
Chakradhar padhan said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].e = 3k(1-2/m)=2c(1+1/m)
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.
Abhay said:
10 years ago
Young's modulus E = 2G(1 + μ) where, G = Modulus of rigidity.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
Gondelamahesh said:
8 years ago
If the modulus of rigidity is 80 kn/mm square and bulk modulus 140 kn/mm square position ratio is what anyone explain it?
Bikash kabiraj said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
Anusha Reddy said:
8 years ago
Good explanation @Ammulu.
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