Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
Discussion:
24 comments Page 2 of 3.
Bikash kabiraj said:
8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.
Anusha Reddy said:
8 years ago
Good explanation @Ammulu.
Abigail said:
9 years ago
I tried d formulae for the relationship between bulk modulus and modulus of rigidity but it's not giving me the right answer.
Can anyone help me?
Can anyone help me?
Ammulu said:
9 years ago
E = 2g(1 + u),
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.
Mujru said:
9 years ago
The equation related to bulk modulus and modulus of rigidity is;
E = 2n(1+u).
E = bulk modulus,
n= modulus of rigidity,
u = possion raito.
So,
u = E/2n -1.
= 200/(80 * 2) - 1.
= 0.25.
E = 2n(1+u).
E = bulk modulus,
n= modulus of rigidity,
u = possion raito.
So,
u = E/2n -1.
= 200/(80 * 2) - 1.
= 0.25.
Krishna said:
9 years ago
You are correct @Rathi.
E = 2G(1+mu)
then u = 0.25.
E = 2G(1+mu)
then u = 0.25.
Abhay said:
10 years ago
Young's modulus E = 2G(1 + μ) where, G = Modulus of rigidity.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
=> μ = E/2G - 1.
=> 200/(2*80) - 1.
= 1.25 - 1.
μ = 0.25.
Susmita said:
1 decade ago
We know that C = mE/2 (m+1).
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
Where C = 80GN/m2.
E = 200GN/m2.
1/m = Poisson's ratio = 0.25.
PIYUSH SINGH said:
1 decade ago
Young modulus = E.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Modulus of Rigidity = G.
Poisson's Ratio = U.
Formula => E = 2G (1-u).
Therefore:
A) 200 = 2*80 (1-u).
B) 1-u = 1.25.
C) u = 1.25-1.
D) u = 0.25.
Mayuri said:
1 decade ago
E = 2G (1-1/m).
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
200 = 2*80(1-1/m).
200 = 160-160/m.
40 = 160/m.
1/m = 40/160.
1/m = 0.25.
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