Civil Engineering - Steel Structure Design - Discussion

Given Data:

Pitch = p = 6cm
Rivet Value = R = 4tonnes
No.of Rivets = n = ?
Eccentric Load=P=15tonnes
Distance b/w Centre Line [ i-e Centroid (G) ] and Line of action of Eccentric Load (P) = e = 30cm.

Sol:

Formula:
n = (6M/R.p)^1/2 -------------(1).

Here,
External Moment=M=P.e/No.of Vertical Rows -------------------(2).
[I don't know why but according to the situation], The No. Of Vertical Rows = 2.

So, Now ,
Putting the values in eqn (2),
M = 15 tonnes*30cm/2.
M = 225 tonnes-cm.

Now ,
Putting all the values in eqn (1).

n=(6*225 tonnes-cm/4tonnes*6cm)^1/2.
n=(56.25)^1/2.
n=7.5.

Take it as n=8rivets.

So,
No. of Rivets=n=8 (And).

The number of rivet lines is not provided. Then how to predict?

After calculating rivet value,

No.of rivets = total load/ rivet Value.

N = (6m/rv)^.5.

What is the value of s?

(6M/lpR)^1/2.

(6x30x15/2x6x4)^1/2.

7.5 answer.

8 rivet.

From which formula I can determine the strength of rivet? Please help me. Thank you.

The simple method to find no. of rivet is-it is the question of bracket connection so in this connection same no. of rivets are required on each flange to connect the bracket.

So each side required. Rivets are = 15/4 = 3.75 = 4 rivets each side, so total no. of rivets required both side for connection are = 8.

What is the formula for strength in shearing and bearing?

According to me,

Mri/(nri2) + p.
n = 15