Civil Engineering - Steel Structure Design - Discussion

Discussion Forum : Steel Structure Design - Section 1 (Q.No. 5)
5.
If the pitch is 6 cm and rivet value is 4 tonnes, the number of rivets required for a riveted connection carrying an eccentric load of 15 tonnes at a distance of 30 cm from the centre line, is
6
8
10
12
15
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 2 of 2.

Sintu Paul said:   8 years ago
@Deepanshu.

How I = 2? Explain.

Naveen pal said:   8 years ago
=> 6m/snRv.
Where m =p*e,
S pick line,
Rv rivet value,
Answer is 7.5 = 8.

Soumyadip said:   1 decade ago
I do find out the formula for tearing the plate is P1 = S1(P-d)t. Here S1 is the allowable tensile stress, p=pitch, d=dia, t=thickness of plate and for the shearing of the rivet is P2=Ss (area of one rivet=0.785*d^2).

Here Ss is the allowable shear stress of the rivet material. So, from this two formula I don't know the "tensile stress" and "shear stress" and "dia of rivet", how can I determine the strength of rivet? Please suggest me.

Thank you.

Hanu said:   8 years ago
@Deepansu it meane 2 line vertical and Rivet is 16 according to formula (you take m =2) and in 1 line 8 rivet.

Herb pelkey said:   1 decade ago
A1 - stainless rod 50 feet long how high from the middle will have to rise to have the ends come in 1 F foot.

Zing Zing said:   8 years ago
Total Revit will be 15 or 16 but if it is said that rabbit in one line then it will be 8 or 7.

Siraj said:   6 years ago
@Asif Bhai, amazed with your explanation. :).

Jayapriya said:   5 years ago
Thank you all for giving the explanation.

Swati Chourasia said:   1 decade ago
Strength of rivet in shearing and bearing are calculated and the lesser value among two is known as rivet value.


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