### Discussion :: Steel Structure Design - Section 1 (Q.No.5)

Swati Chourasia said: (Jun 28, 2013) | |

Strength of rivet in shearing and bearing are calculated and the lesser value among two is known as rivet value. |

Balkaran Sidhu said: (Jan 18, 2014) | |

After calculating rivet value, No.of rivets = total load/ rivet Value. |

Deepanshu said: (Aug 22, 2014) | |

(6M/lpR)^1/2. (6x30x15/2x6x4)^1/2. 7.5 answer. 8 rivet. |

Herb Pelkey said: (Feb 28, 2015) | |

A1 - stainless rod 50 feet long how high from the middle will have to rise to have the ends come in 1 F foot. |

Soumyadip said: (Jun 6, 2015) | |

I do find out the formula for tearing the plate is P1 = S1(P-d)t. Here S1 is the allowable tensile stress, p=pitch, d=dia, t=thickness of plate and for the shearing of the rivet is P2=Ss (area of one rivet=0.785*d^2). Here Ss is the allowable shear stress of the rivet material. So, from this two formula I don't know the "tensile stress" and "shear stress" and "dia of rivet", how can I determine the strength of rivet? Please suggest me. Thank you. |

Soumyadip said: (Jun 6, 2015) | |

From which formula I can determine the strength of rivet? Please help me. Thank you. |

Gurpreet Singh said: (Aug 7, 2015) | |

The simple method to find no. of rivet is-it is the question of bracket connection so in this connection same no. of rivets are required on each flange to connect the bracket. So each side required. Rivets are = 15/4 = 3.75 = 4 rivets each side, so total no. of rivets required both side for connection are = 8. |

Agni said: (Sep 29, 2016) | |

What is the formula for strength in shearing and bearing? |

Saurabh Pal said: (Oct 20, 2016) | |

According to me, Mri/(nri2) + p. n = 15 |

Sintu Paul said: (Mar 26, 2017) | |

@Deepanshu. How I = 2? Explain. |

Naveen Pal said: (Jul 29, 2017) | |

=> 6m/snRv. Where m =p*e, S pick line, Rv rivet value, Answer is 7.5 = 8. |

Sejal said: (Aug 14, 2017) | |

What is the value of s? |

Hanu said: (Nov 11, 2017) | |

@Deepansu it meane 2 line vertical and Rivet is 16 according to formula (you take m =2) and in 1 line 8 rivet. |

Asif Ali said: (Nov 11, 2017) | |

Given Data: Pitch = p = 6cm Rivet Value = R = 4tonnes No.of Rivets = n = ? Eccentric Load=P=15tonnes Distance b/w Centre Line [ i-e Centroid (G) ] and Line of action of Eccentric Load (P) = e = 30cm. Sol: Formula: n = (6M/R.p)^1/2 -------------(1). Here, External Moment=M=P.e/No.of Vertical Rows -------------------(2). [I don't know why but according to the situation], The No. Of Vertical Rows = 2. So, Now , Putting the values in eqn (2), M = 15 tonnes*30cm/2. M = 225 tonnes-cm. Now , Putting all the values in eqn (1). n=(6*225 tonnes-cm/4tonnes*6cm)^1/2. n=(56.25)^1/2. n=7.5. Take it as n=8rivets. So, No. of Rivets=n=8 (And). |

Zing Zing said: (Jan 19, 2018) | |

Total Revit will be 15 or 16 but if it is said that rabbit in one line then it will be 8 or 7. |

Siraj said: (Dec 31, 2019) | |

@Asif Bhai, amazed with your explanation. :). |

Jayapriya said: (Apr 18, 2020) | |

Thank you all for giving the explanation. |

Pramit Samanta said: (Mar 4, 2021) | |

The number of rivet lines is not provided. Then how to predict? |

Vina said: (May 9, 2021) | |

N = (6m/rv)^.5. |

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