Civil Engineering - Steel Structure Design - Discussion


If the pitch is 6 cm and rivet value is 4 tonnes, the number of rivets required for a riveted connection carrying an eccentric load of 15 tonnes at a distance of 30 cm from the centre line, is

[A]. 6
[B]. 8
[C]. 10
[D]. 12
[E]. 15

Answer: Option B


No answer description available for this question.

Swati Chourasia said: (Jun 28, 2013)  
Strength of rivet in shearing and bearing are calculated and the lesser value among two is known as rivet value.

Balkaran Sidhu said: (Jan 18, 2014)  
After calculating rivet value,

No.of rivets = total load/ rivet Value.

Deepanshu said: (Aug 22, 2014)  


7.5 answer.

8 rivet.

Herb Pelkey said: (Feb 28, 2015)  
A1 - stainless rod 50 feet long how high from the middle will have to rise to have the ends come in 1 F foot.

Soumyadip said: (Jun 6, 2015)  
I do find out the formula for tearing the plate is P1 = S1(P-d)t. Here S1 is the allowable tensile stress, p=pitch, d=dia, t=thickness of plate and for the shearing of the rivet is P2=Ss (area of one rivet=0.785*d^2).

Here Ss is the allowable shear stress of the rivet material. So, from this two formula I don't know the "tensile stress" and "shear stress" and "dia of rivet", how can I determine the strength of rivet? Please suggest me.

Thank you.

Soumyadip said: (Jun 6, 2015)  
From which formula I can determine the strength of rivet? Please help me. Thank you.

Gurpreet Singh said: (Aug 7, 2015)  
The simple method to find no. of rivet is-it is the question of bracket connection so in this connection same no. of rivets are required on each flange to connect the bracket.

So each side required. Rivets are = 15/4 = 3.75 = 4 rivets each side, so total no. of rivets required both side for connection are = 8.

Agni said: (Sep 29, 2016)  
What is the formula for strength in shearing and bearing?

Saurabh Pal said: (Oct 20, 2016)  
According to me,

Mri/(nri2) + p.
n = 15

Sintu Paul said: (Mar 26, 2017)  

How I = 2? Explain.

Naveen Pal said: (Jul 29, 2017)  
=> 6m/snRv.
Where m =p*e,
S pick line,
Rv rivet value,
Answer is 7.5 = 8.

Sejal said: (Aug 14, 2017)  
What is the value of s?

Hanu said: (Nov 11, 2017)  
@Deepansu it meane 2 line vertical and Rivet is 16 according to formula (you take m =2) and in 1 line 8 rivet.

Asif Ali said: (Nov 11, 2017)  
Given Data:

Pitch = p = 6cm
Rivet Value = R = 4tonnes
No.of Rivets = n = ?
Eccentric Load=P=15tonnes
Distance b/w Centre Line [ i-e Centroid (G) ] and Line of action of Eccentric Load (P) = e = 30cm.


n = (6M/R.p)^1/2 -------------(1).

External Moment=M=P.e/No.of Vertical Rows -------------------(2).
[I don't know why but according to the situation], The No. Of Vertical Rows = 2.

So, Now ,
Putting the values in eqn (2),
M = 15 tonnes*30cm/2.
M = 225 tonnes-cm.

Now ,
Putting all the values in eqn (1).

n=(6*225 tonnes-cm/4tonnes*6cm)^1/2.

Take it as n=8rivets.

No. of Rivets=n=8 (And).

Zing Zing said: (Jan 19, 2018)  
Total Revit will be 15 or 16 but if it is said that rabbit in one line then it will be 8 or 7.

Siraj said: (Dec 31, 2019)  
@Asif Bhai, amazed with your explanation. :).

Jayapriya said: (Apr 18, 2020)  
Thank you all for giving the explanation.

Pramit Samanta said: (Mar 4, 2021)  
The number of rivet lines is not provided. Then how to predict?

Vina said: (May 9, 2021)  
N = (6m/rv)^.5.

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