Civil Engineering - Steel Structure Design - Discussion

Discussion Forum : Steel Structure Design - Section 1 (Q.No. 5)
5.
If the pitch is 6 cm and rivet value is 4 tonnes, the number of rivets required for a riveted connection carrying an eccentric load of 15 tonnes at a distance of 30 cm from the centre line, is
6
8
10
12
15
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Vina said:   4 years ago
N = (6m/rv)^.5.
(1)

Pramit Samanta said:   4 years ago
The number of rivet lines is not provided. Then how to predict?
(3)

Jayapriya said:   5 years ago
Thank you all for giving the explanation.

Siraj said:   6 years ago
@Asif Bhai, amazed with your explanation. :).

Zing Zing said:   8 years ago
Total Revit will be 15 or 16 but if it is said that rabbit in one line then it will be 8 or 7.

Asif Ali said:   8 years ago
Given Data:

Pitch = p = 6cm
Rivet Value = R = 4tonnes
No.of Rivets = n = ?
Eccentric Load=P=15tonnes
Distance b/w Centre Line [ i-e Centroid (G) ] and Line of action of Eccentric Load (P) = e = 30cm.

Sol:

Formula:
n = (6M/R.p)^1/2 -------------(1).

Here,
External Moment=M=P.e/No.of Vertical Rows -------------------(2).
[I don't know why but according to the situation], The No. Of Vertical Rows = 2.

So, Now ,
Putting the values in eqn (2),
M = 15 tonnes*30cm/2.
M = 225 tonnes-cm.

Now ,
Putting all the values in eqn (1).

n=(6*225 tonnes-cm/4tonnes*6cm)^1/2.
n=(56.25)^1/2.
n=7.5.

Take it as n=8rivets.

So,
No. of Rivets=n=8 (And).
(11)

Hanu said:   8 years ago
@Deepansu it meane 2 line vertical and Rivet is 16 according to formula (you take m =2) and in 1 line 8 rivet.

Sejal said:   8 years ago
What is the value of s?
(1)

Naveen pal said:   8 years ago
=> 6m/snRv.
Where m =p*e,
S pick line,
Rv rivet value,
Answer is 7.5 = 8.

Sintu Paul said:   8 years ago
@Deepanshu.

How I = 2? Explain.


Post your comments here:

Your comments will be displayed after verification.