Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 1)
1.
For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be
Discussion:
24 comments Page 1 of 3.
Brijendra said:
1 decade ago
P=WH, H=P/W, H=48/.8=60.
Rashid said:
9 years ago
Hi, @Brijendra.
How you take 4.8 as 48?
How you take 4.8 as 48?
Binktesh kumar said:
9 years ago
Hello, @Brijendra.
How you take pressure 4.8 to 48?
How you take pressure 4.8 to 48?
Shubham said:
9 years ago
@Brijendra.
Tell me how you converted 4.8 to 48?
Tell me how you converted 4.8 to 48?
Honey said:
9 years ago
Here, it is converted it in newton by multiplying 10.
Another way to do it is, 1st convert 4.8kg/cm2 into kg/m2 by multiplying it with 10000.
Ten again multiply by 10 to get in N/m2, then find out the specific weight.
=> 8 * 1000 * 10 now divide 480000/8000.
You will get 60 as an answer.
Another way to do it is, 1st convert 4.8kg/cm2 into kg/m2 by multiplying it with 10000.
Ten again multiply by 10 to get in N/m2, then find out the specific weight.
=> 8 * 1000 * 10 now divide 480000/8000.
You will get 60 as an answer.
Disha said:
9 years ago
Explain briefly!
Sasi said:
9 years ago
Pressure = W * H.
4.8 * 10^3 = sp. grvty * dnsty * H.
4800 = 0.8 * 1* H.
H = 6000cm = 60m.
4.8 * 10^3 = sp. grvty * dnsty * H.
4800 = 0.8 * 1* H.
H = 6000cm = 60m.
Rind said:
9 years ago
H = p/w.
= 48/.8,
= 60.
= 48/.8,
= 60.
Abhishek Anand said:
9 years ago
Answer must be 60m. I agree.
BASTARD said:
8 years ago
PRESSURE=(UNIT WT.)*(HEIGHT).
4.8 = (0.8)*(1000/100^3)*(H),
H = 6000 cm.
H = 60 m.
4.8 = (0.8)*(1000/100^3)*(H),
H = 6000 cm.
H = 60 m.
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