Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 1)
1.
For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be
Discussion:
24 comments Page 1 of 3.
Kishor bist dadeldhura said:
1 year ago
1kg/cm2 = (10/s.g)m of any fluid.
4.8kg/cm2 = (4.8×10)/0.8m of oil.
= 60m of oil.
4.8kg/cm2 = (4.8×10)/0.8m of oil.
= 60m of oil.
(1)
Nasir Rasool said:
4 years ago
60m is the right answer.
(1)
Masum said:
5 years ago
Yes, it should be 60m.
(2)
Jafar said:
5 years ago
1 kg=9.81 N so P=4.8kg/cm2 which is equal to 4.8 x 9.81 x 10000 N/m2(1m = 100cm).
So now P=w.h where w=spG unit wt of water=0.8 x 9.81.
hence h=60000 cm or 60m.
So now P=w.h where w=spG unit wt of water=0.8 x 9.81.
hence h=60000 cm or 60m.
(2)
Vim said:
5 years ago
P= 4.8*10^4Kg/m^2.
pressure head= p/y = 4.8*10^4/ 0.8*1000.
= 60m.
pressure head= p/y = 4.8*10^4/ 0.8*1000.
= 60m.
(1)
Bhim said:
5 years ago
It should be 60m not 60cm.
(1)
Sumanta said:
6 years ago
It should be 60 m not 60 cm.
(1)
Spsiro said:
6 years ago
(4.8*10000*10)/(.8*1000*10) = 60m is the correct answer.
(1)
Ramyahegde said:
7 years ago
P = wh.
w = 1 g/cc = 1000kg/cc.
P = 4.8kg/cm^2 = 4.8 * 10^4 kg/m^2.
4.8 * 10^4 = 0.8 * 1000 vh.
48 = 0.8h.
h = 48/0.8.
h = 60m.
w = 1 g/cc = 1000kg/cc.
P = 4.8kg/cm^2 = 4.8 * 10^4 kg/m^2.
4.8 * 10^4 = 0.8 * 1000 vh.
48 = 0.8h.
h = 48/0.8.
h = 60m.
(3)
Khalid raza said:
7 years ago
P = 4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers