Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 1)
1.
For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be
Discussion:
24 comments Page 2 of 3.
BIBEK said:
8 years ago
Answer 60 m is correct. I agree.
Sanjay said:
8 years ago
Yes, they all are right, the answer must be in a meter.
MaNiSh said:
8 years ago
@ALL.
P=4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
P=4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
Sadulla Ahmed said:
7 years ago
Yes, it's 60m. I agree.
Khalid raza said:
7 years ago
P = 4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
(1)
Ramyahegde said:
7 years ago
P = wh.
w = 1 g/cc = 1000kg/cc.
P = 4.8kg/cm^2 = 4.8 * 10^4 kg/m^2.
4.8 * 10^4 = 0.8 * 1000 vh.
48 = 0.8h.
h = 48/0.8.
h = 60m.
w = 1 g/cc = 1000kg/cc.
P = 4.8kg/cm^2 = 4.8 * 10^4 kg/m^2.
4.8 * 10^4 = 0.8 * 1000 vh.
48 = 0.8h.
h = 48/0.8.
h = 60m.
(3)
Spsiro said:
6 years ago
(4.8*10000*10)/(.8*1000*10) = 60m is the correct answer.
(1)
Sumanta said:
6 years ago
It should be 60 m not 60 cm.
(1)
Bhim said:
5 years ago
It should be 60m not 60cm.
(1)
Vim said:
5 years ago
P= 4.8*10^4Kg/m^2.
pressure head= p/y = 4.8*10^4/ 0.8*1000.
= 60m.
pressure head= p/y = 4.8*10^4/ 0.8*1000.
= 60m.
(1)
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