Civil Engineering - Estimating and Costing - Discussion

Discussion Forum : Estimating and Costing - Section 1 (Q.No. 22)
22.
For 12 mm thick cement plastering 1 : 6 on 100 sq.m new brick work, the quantity of cement required, is
0.200 m3
0.247 m3
0.274 m3
0.295 m3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
43 comments Page 1 of 5.

Swarnim said:   1 year ago
Area to be plaster = 100m^2.
Thickness of plaster = 12mm = 0.012m.
The volume of plaster = 100x0.012 = 1.2m^3.
Adding 20%of wet volume,
= 1.2 + 1.2 x 20% = 1.44m^3.

Increase the wet material by 33% (generally, as range is 30-35%) volume in order to get dry volume.

The volume of dry material = 1.44 + 1.44 x .33 = 1.952 m^3.

Now, volume of cement = 1/7x1.952 = 0.2736 m^3 on rounding off it will be equal to 0.274 m^3 as per answer.
(12)

SHOHEL said:   2 years ago
The Correct answer is 0.247 m3.
(1)

KAMALENDU said:   2 years ago
(60/100) X 1.2 + 1.2.
= 1.92/1+6.
= 0.274.
60% water.
100 x 0.012 = 1.2 m3.
(4)

Ankit kumar singh said:   2 years ago
The vol of plaster=0.012*100 = 1.2.
12 mm thickness is used;
So for vol of wet mortar increment is done by 30%.
(if 15 mm then 25%, if 20 mm then 20%)
Now vol of wet mortar =1.2 * 1.3 = 1.56.

(25% increment in wet mortar for vol of dry mortar)
The vol of dry mortar =1.56 * 1.25 = 1.95.
The vol of cement =1/7 * 1.95 = 0.278.
(19)

Philip Isabirye said:   3 years ago
Interesting, Thanks all for explaining.
(3)

Tarkraj said:   3 years ago
No, it's wrong.

In mortar or plastering, we increase only by 30%.

But for PCC we increase 50-55%.
(3)

Narendra saud said:   3 years ago
You can take 30% for uniform wall and 25% for dry volume i.e. total of 55%.
Now, 10x10x0.012 = 1.2
Hence (1.2/1+6)+(1.2/1+6)x55/100 = 0.2785.
(6)

Vintage said:   3 years ago
Plastering thickness 12 mmc= 12/1000 = 0.012m.

Volume of cement mortar required = (Plastering Area x thickness) = 100 m2 x 0.012m = 1.2 m3
(This is a wet volume which means we need this much volume of cement mortar after mixing water.

So, for dry volume, we have to add 30-35% as bulkage of sand, we are using 35% and wastage as 20%).

Consider 35% Sand Bulkage = 1.2 m3 x (1 + 0.2 + 0.35) = 1.86 m3
Cement required = (1/7) x 1.86 = 0.265 m3.
(8)

Basanta said:   3 years ago
It's for 0.247m3.
(2)

Lilly said:   4 years ago
Adding 30 per extra for uneven surface and to fill up joints.


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