### Discussion :: Estimating and Costing - Section 1 (Q.No.22)

P Takhe Lomdak said: (Oct 2, 2013) | |

How it is calculated out please tell me the procedure? |

Mukund said: (Dec 13, 2013) | |

Total volume = 100*.012 = 1.2cum. 30% more mortar required so 1.2+ (.3*1.20) = 1.56cum. Now also to get dry volume of mortar, wet wet volume may b further increase by 25%. So volume of dry mortar = 1.6+ (1.56*.25) = 1.95cum. Now proportion = 1:6. So volume of cement = (1/7) * 1.95 = 0.2785 (ans). |

Chandu said: (Jan 27, 2014) | |

Given volume = 100*.012 = 1.2cum. Increase mortar by 30% = 1.56cum. For volume of dry mortar increase 25%= 1.56+ (1.56*.25) = 1.95cum. Now proportion = 1:6. k+6k=7k. So volume of cement = (1/7) * 1.95 = 0.2785. This is the correct answer. |

Ajay Saini said: (Apr 23, 2014) | |

You can take 30% for uniform wall and 25% for dry volume i.e. total 55% Now 10x10x0.012 = 1.2 hence (1.2/1+6)+(1.2/1+6)x55/100 = 0.2785. |

Pritam said: (Jul 30, 2014) | |

How could you take, extra 30% morter? |

Piyush Singh said: (Sep 9, 2014) | |

Volume of plaster = area * thickness = 0.012*100 = 1.2 cum. Increase this by 30 % therefore = 1.2*1.3 = 1.56 cum. For volume of dry mortar = 1.25*1.56 = 1.95 cum. Now 1 part is of cement and 6 part is of sand so, Cement = (1/7) *1.95= 0.2785 volume of cement. Volume of one bag of cement = 0.035 cum. So no of bags required = 8 bags. |

Nivas said: (Sep 18, 2014) | |

Is is possible go around 55% volume extra for dry & wet mortar? |

Abhijit Mandal said: (Jan 21, 2016) | |

Volume of plaster = 0.012*100 = 1.2 m^3. Add 20% depression & wastages volume of plaster = 1.2+1.2*20% = 1.2+0.24 = 1.44. Add 1/3 dry volume = 1.44+1.44*1/3 = 1.44+0.48 = 1.92 m^3. Cement = 1.92*1/7 = 0.274 m^3. |

Adebola said: (Sep 13, 2016) | |

I think answers may vary because one may decide to allow 10-20% for wastage& 30%-35% for shrinkage. |

Brijesh Vishwakarma said: (Sep 14, 2016) | |

Volume of plaster = 0.012 * 100 = 1.2 m^3. Add 60% for new wall depression & wastages volume of plaster = 1.2 + 1.2 * 60% = 1.92 cum. Cement = 1.92 * 1/7 = 0.274 m^3. |

Puja Mandal said: (Nov 27, 2016) | |

According to me, it is .012 * 100 = 1.2, dry wt = 1.54 * 1.2 = 1.848, 1.848 ÷ 7 = .264. |

Aaina said: (Feb 23, 2017) | |

If it's 15mm thick then what is the answer? |

Arjun said: (Feb 25, 2017) | |

As per my solution, it's 33 percent extra why you are taking 30 percent? |

Sufazo said: (Mar 28, 2017) | |

According to this answer, they taking 60% extra => 1.2 * 60/100 = 0.274. |

Shahanshah Khan said: (Nov 14, 2017) | |

I think dry value taken so large in solution maximum take extra 20% to 30%. |

Mohit said: (Dec 26, 2017) | |

If it is 15 mm thick than answer is .345 cum. |

Salma said: (Jan 10, 2018) | |

1*100*. 012*1. 54/7 =. 274. |

Adhiyaman said: (Jan 10, 2018) | |

Thanks to all. |

Mohit Motwani said: (Jan 30, 2018) | |

Volume of mortar required= 100*.12 = 1.2. Total 60% of volume increases for dry mortar 1.2+ (.60* 1.2)= 1.92. Now volume of cement = 1/7 * 1.92= 0.2743. |

Muthu Nayak said: (Mar 7, 2018) | |

dry vol=area*thckness*1.3*1.25. dry vol=100*0.012*1.3*1.25. =1.95cum, Cement=1.95/1+6, Cement=0.278cum, |

Sachin Das said: (Apr 23, 2018) | |

For 1 m3, Dry volume = 1m3, Wet volume is 35% of dry volume, So we have to take. 1: 6 = 1.35 ( 1.35 m3 become 1m3 after adding water in mortor....and for concrete we take 55%....1.54m3 = 1m3). 1+ 6 = 7........1.35/7 = 0.193 cement required per m3, Volume = 12/1000 * 100 = 1.2 m3, Required cement volume= 1.2 * 0.193 =0.23. |

Naveen Srivastava said: (Sep 29, 2018) | |

0.278 is the incorrect answer. There is no need to add an extra 25%. It's Converted to wet volume to dry volume by 1.30. The Correct ans is 100 * 0.012 * 1.30 = 1.56 * (1/7) = 0.222cum. |

Deepak said: (Oct 4, 2018) | |

Why to increase by its 30%? |

Matiur Rahaman said: (Nov 21, 2018) | |

Given thickness of plaster = 12mm = 12/1000 m = 0.012m. Ratio (1:6). Since you have not given assume that 100 sq M of plaster is Done. Thus volume of plaster = 100 x 0.012 =1.2 cum. Add 60 % for unevenness of plaster surface and voids. Total volume of plaster work = 1.2 + 60/100 x 1.2 =1.92 cum. Volume of cement = 1.92/(1+6) =0.274 cum. |

Ramvir Singh said: (Dec 26, 2018) | |

@All We will take 60% extra of total Volume for water and joint filling between the bricks. So, 1 for 15mm thick plasters the answer is 0.3428 m3 and For 12 mm thick plaster it is 0.2742 m3. |

Shree said: (Jun 5, 2019) | |

Wet mix mortar for uniform layer =12/1000*100 = 1.2 cum. Adding 30% to fill up joints, uneven surface, Then, Quantity of Mortar =1.2 + 1.2*30% =1.56 cum. Increasing 25% the dry volume = 1.56+1.56*25%= 1.95 cum. Total parts (C:S) = 1+6 =7. Then, Cement = 1.95/7 = 0.278 Cum = 0.278/0.0347 = 8 Bags Cement required. |

Bharat said: (Jul 16, 2019) | |

Thanks all. |

Govind said: (Sep 9, 2019) | |

Thanks everyone for explaining the solution. |

Jigme said: (Sep 15, 2019) | |

Thank you all for explaining the answer, clearly. |

Dinesh Sunar said: (Nov 24, 2019) | |

Area to be plaster = 100m^2. Thickness of plaster = 12mm = 0.012m. The volume of plaster = 100x0.012 = 1.2m^3. Adding 20%of wet volume, = 1.2+1.2x20% = 1.44m^3. Increase the wet material by 1/3rd volume in order to get dry volume. The volume of dry material = 1.44+1.44x1/3. , ,, = 1.92 m^3. Now, volume of cement = 1/7x1.92 = 0.274. |

Hari said: (Aug 23, 2020) | |

Why we take 30% extra? Please explain. |

Kaku said: (Sep 30, 2020) | |

The correct answer is 0.2228m3. |

Jon said: (Dec 2, 2020) | |

Why take 30% extra here? Please explain me. |

#### Post your comments here:

Name *:

Email : (optional)

» Your comments will be displayed only after manual approval.