Civil Engineering - Construction Management - Discussion

Discussion Forum : Construction Management - Section 2 (Q.No. 33)
33.
Optimistic time, most likely time and pessimistic times for the activities of a network in the given figure are written above their arrows. If the contractual obligation time for the project is 75, the latest occurrence time for the event 2, is
20
25
35
15
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Kajal Tomar said:   7 years ago
Latest occurrence time calculated from backward pass method.

Therefore TL of event 4 is 75 given;
Now( 75- (TE of 3-4) - (TE of2-3)),
TE =( opt time + 4 *most lik time + pess time) /6.
75 - (15) - (35) = 25 i.e TL of event 2 i.e asked.
(6)

Pranab said:   9 years ago
It is considering 1-2, the contractual obligation 75 and latest occurrence is 2. It is considering latest occurrence 1-2.

{PT + (4 x MLT) + OT}/6.
i.e {15+(4x28)+21}/6 which is equal to 24.66.

But, contractual obligation 75,
From event 1-2, 2-3, and 3-4 total 3 duration time,
so, time duration to reach 1-2 is 75/3 = 25,
25>24.66.
Due to contractual obligation, the time will be the greater one
Ans = 25.
(5)

Sooraj said:   3 years ago
Thanks @Pranab @Kajal.
(2)

Hassan said:   4 years ago
@Kajal Tomar:.

What is TL here? Explain please.
(2)

Jesi said:   3 years ago
Thank you @Kajal.
(1)

Devendra Rimal said:   3 years ago
You are right, Thanks @Kajal Timar.
(1)

Naveen B said:   1 decade ago
{Op time + (4 * Most lik time) + pess time}/6.

i.e {15+(4*28)+21}/6 which is equal to 24.6666 = 25.
(1)

AKHILA said:   6 years ago
Thanks @Kajal Tomar.

Dhwani said:   4 years ago
Yes, Agree @Kajal.

Assumi said:   4 years ago
@Hassan.

TL is the latest occurrence time.


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