Civil Engineering - Construction Management - Discussion
Discussion Forum : Construction Management - Section 2 (Q.No. 33)
33.
Optimistic time, most likely time and pessimistic times for the activities of a network in the given figure are written above their arrows. If the contractual obligation time for the project is 75, the latest occurrence time for the event 2, is
Discussion:
17 comments Page 1 of 2.
Naveen B said:
1 decade ago
{Op time + (4 * Most lik time) + pess time}/6.
i.e {15+(4*28)+21}/6 which is equal to 24.6666 = 25.
i.e {15+(4*28)+21}/6 which is equal to 24.6666 = 25.
(1)
Rituraj said:
10 years ago
Is this is possible that pessimistic time can be less than optimistic time? Please answer this.
Amjad said:
10 years ago
Then what is the contractual obligation 75 and latest occurrence is 2?
Amjad said:
10 years ago
Then what is the contractual obligation 75 and latest occurrence is 2?
Amjad said:
10 years ago
Then what is the contractual obligation 75 and latest occurrence is 2?
Pranab said:
9 years ago
It is considering 1-2, the contractual obligation 75 and latest occurrence is 2. It is considering latest occurrence 1-2.
{PT + (4 x MLT) + OT}/6.
i.e {15+(4x28)+21}/6 which is equal to 24.66.
But, contractual obligation 75,
From event 1-2, 2-3, and 3-4 total 3 duration time,
so, time duration to reach 1-2 is 75/3 = 25,
25>24.66.
Due to contractual obligation, the time will be the greater one
Ans = 25.
{PT + (4 x MLT) + OT}/6.
i.e {15+(4x28)+21}/6 which is equal to 24.66.
But, contractual obligation 75,
From event 1-2, 2-3, and 3-4 total 3 duration time,
so, time duration to reach 1-2 is 75/3 = 25,
25>24.66.
Due to contractual obligation, the time will be the greater one
Ans = 25.
(5)
Kajal Tomar said:
7 years ago
Latest occurrence time calculated from backward pass method.
Therefore TL of event 4 is 75 given;
Now( 75- (TE of 3-4) - (TE of2-3)),
TE =( opt time + 4 *most lik time + pess time) /6.
75 - (15) - (35) = 25 i.e TL of event 2 i.e asked.
Therefore TL of event 4 is 75 given;
Now( 75- (TE of 3-4) - (TE of2-3)),
TE =( opt time + 4 *most lik time + pess time) /6.
75 - (15) - (35) = 25 i.e TL of event 2 i.e asked.
(6)
Dan said:
7 years ago
You are right @Kajal Tomar.
AKHILA said:
6 years ago
Thanks @Kajal Tomar.
Sadulla said:
5 years ago
Right, Thanks @Kajal.
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