Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
32 comments Page 1 of 4.
Haritha said:
1 decade ago
Why did we take volume of water displaced here?
Suraj said:
1 decade ago
From where 0. 01 comes?
Thenmozhi said:
1 decade ago
How density of water calculated ?
Gurpreet said:
1 decade ago
Why did we take volume of water displaced here?
How density of water calculated?
How density of water calculated?
Ramanathan said:
1 decade ago
When an object is immersed in water the volume of water displaced by the object is not equal to the mass of object. It is equal to the volume of object. In this case the volume of man is 0.06 cubic meters. We should know the density of man to calculate the mass of man, not density of water.
Mrinal said:
1 decade ago
The height is given 1cm when it sinks, so H is 0.01m.
Hannan said:
1 decade ago
How density of water is measured? Can anybody help me please.
SVK said:
1 decade ago
@Hannan.
Density of H2O IS 1000kg/m3.
Google density of water and it gives you 1000kg/m3.
Density of H2O IS 1000kg/m3.
Google density of water and it gives you 1000kg/m3.
Sabha said:
1 decade ago
Density of water always 1000kg/m3.
Raju subba said:
1 decade ago
How is the density of water calculated?
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