# Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
12 kg
60 kg
72 kg
96 kg
Explanation:

 Volume of water displaced = (3 x 2 x 0.01) m3 = 0.06 m3.

 Mass of man = Volume of water displaced x Density of water = (0.06 x 1000) kg = 60 kg.

Discussion:
32 comments Page 1 of 4.

Keenly said:   2 years ago
From where 0.01 came? Please explain me.

Pratik said:   2 years ago
In ship stability,

Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
(2)

Soumyajit Routray said:   2 years ago
Where 0.01 comes? Please explain.

Suneel_kushawaha said:   3 years ago
Inside the water pressure = Ïgh;

And force = pressure X Area. that is equal to the weight of the man.
So, Mg = Ïghlb.
=>M= Ïhlb.

Sri said:   3 years ago
The Default value of water density is 1000Kg/m3.
(1)

Bhuvi said:   4 years ago
The density of water is unity. And 1 cm when converted to m it becomes 0. 01m.

Sanket kapse said:   4 years ago
How the Density is 1000? Please explain me.
(2)

Subash chander said:   4 years ago
Volume of boat lbh.

Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.
The volume of that region = volume of the man in water.
0.06= mass/density.
0.06 x density = mass.
0.06 x 1000 = mass.
Mass of the man = 60kg.
(1)

Shailesh jahav said:   4 years ago
Please explain the formula in detail.

Vivek said:   4 years ago
Vol of ship = Weight of Man + Vol of Ship after shink.
LxBxH = M + LxBx (H-1).

Can't it be done like this? Please tell me.