Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
32 comments Page 1 of 4.
Keenly said:
2 years ago
From where 0.01 came? Please explain me.
Pratik said:
2 years ago
In ship stability,
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
(2)
Soumyajit Routray said:
2 years ago
Where 0.01 comes? Please explain.
Suneel_kushawaha said:
3 years ago
Inside the water pressure = Ïgh;
And force = pressure X Area. that is equal to the weight of the man.
So, Mg = Ïghlb.
=>M= Ïhlb.
And force = pressure X Area. that is equal to the weight of the man.
So, Mg = Ïghlb.
=>M= Ïhlb.
Sri said:
3 years ago
The Default value of water density is 1000Kg/m3.
(1)
Bhuvi said:
4 years ago
The density of water is unity. And 1 cm when converted to m it becomes 0. 01m.
Sanket kapse said:
4 years ago
How the Density is 1000? Please explain me.
(2)
Subash chander said:
4 years ago
Volume of boat lbh.
Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.
The volume of that region = volume of the man in water.
0.06= mass/density.
0.06 x density = mass.
0.06 x 1000 = mass.
Mass of the man = 60kg.
Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.
The volume of that region = volume of the man in water.
0.06= mass/density.
0.06 x density = mass.
0.06 x 1000 = mass.
Mass of the man = 60kg.
(1)
Shailesh jahav said:
4 years ago
Please explain the formula in detail.
Vivek said:
4 years ago
Vol of ship = Weight of Man + Vol of Ship after shink.
LxBxH = M + LxBx (H-1).
Can't it be done like this? Please tell me.
LxBxH = M + LxBx (H-1).
Can't it be done like this? Please tell me.
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