# Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)

6.

A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:

Answer: Option

Explanation:

Volume of water displaced | = (3 x 2 x 0.01) m^{3} |

= 0.06 m^{3}. |

Mass of man | = Volume of water displaced x Density of water |

= (0.06 x 1000) kg | |

= 60 kg. |

Discussion:

32 comments Page 1 of 4.
Keenly said:
2 years ago

From where 0.01 came? Please explain me.

Pratik said:
2 years ago

In ship stability,

Displacement of the ship (mass of ship) = under water volume of the ship - density of water.

Displacement of the ship (mass of ship) = under water volume of the ship - density of water.

(2)

Soumyajit Routray said:
2 years ago

Where 0.01 comes? Please explain.

Suneel_kushawaha said:
3 years ago

Inside the water pressure = Ïgh;

And force = pressure X Area. that is equal to the weight of the man.

So, Mg = Ïghlb.

=>M= Ïhlb.

And force = pressure X Area. that is equal to the weight of the man.

So, Mg = Ïghlb.

=>M= Ïhlb.

Sri said:
3 years ago

The Default value of water density is 1000Kg/m3.

(1)

Bhuvi said:
4 years ago

The density of water is unity. And 1 cm when converted to m it becomes 0. 01m.

Sanket kapse said:
4 years ago

How the Density is 1000? Please explain me.

(2)

Subash chander said:
4 years ago

Volume of boat lbh.

Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.

The volume of that region = volume of the man in water.

0.06= mass/density.

0.06 x density = mass.

0.06 x 1000 = mass.

Mass of the man = 60kg.

Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.

The volume of that region = volume of the man in water.

0.06= mass/density.

0.06 x density = mass.

0.06 x 1000 = mass.

Mass of the man = 60kg.

(1)

Shailesh jahav said:
4 years ago

Please explain the formula in detail.

Vivek said:
4 years ago

Vol of ship = Weight of Man + Vol of Ship after shink.

LxBxH = M + LxBx (H-1).

Can't it be done like this? Please tell me.

LxBxH = M + LxBx (H-1).

Can't it be done like this? Please tell me.

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