Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
32 comments Page 2 of 4.
Harsha said:
6 years ago
@skd.
1cm = 0.01m.
1cm = 0.01m.
Priya said:
7 years ago
By using the concept of buoyancy I couldn't understand.
Please help me, @Mihir Jha.
Please help me, @Mihir Jha.
Skd said:
7 years ago
Please define 0.01 where it comes from?
Kapil said:
8 years ago
Why not the mass is 72kg?
Mihir jha said:
8 years ago
Hi friends, we can do this sum by applying the concept of buoyancy.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Latha said:
8 years ago
It is solved by using Archimedes principle.
Varun said:
8 years ago
How volume of water is taken as l*b*h?
Aliza mir said:
8 years ago
@Suhaas, via the Archimedes principle.
Suhaas said:
8 years ago
How volume of water displaced is equal to the mass of a man?
Ashish said:
9 years ago
Simple density is mass per unit vol.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
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