Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
33 comments Page 1 of 4.
Moses said:
1 decade ago
Guys, remember from the question, the man sat on the boat and the boat was floating meaning that his weight is equal to the weight of the fluid displaced (Archimedes principle).
But Density = Mass/Volume. Make mass the subject you get.
Mass of water displaced = Volume of water displaced x Density of water.
So from the above explanation, Mass of the man = Mass of water displaced.
Hence Mass of man = Volume of water displaced x Density of water.
But Density = Mass/Volume. Make mass the subject you get.
Mass of water displaced = Volume of water displaced x Density of water.
So from the above explanation, Mass of the man = Mass of water displaced.
Hence Mass of man = Volume of water displaced x Density of water.
Ramanathan said:
1 decade ago
When an object is immersed in water the volume of water displaced by the object is not equal to the mass of object. It is equal to the volume of object. In this case the volume of man is 0.06 cubic meters. We should know the density of man to calculate the mass of man, not density of water.
Mihir jha said:
9 years ago
Hi friends, we can do this sum by applying the concept of buoyancy.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Subash chander said:
5 years ago
Volume of boat lbh.
Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.
The volume of that region = volume of the man in water.
0.06= mass/density.
0.06 x density = mass.
0.06 x 1000 = mass.
Mass of the man = 60kg.
Volume of the region immersed due to the man get on the boat is l x b x 0.01 =3 x 2 x 0.01 =0.06 m.
The volume of that region = volume of the man in water.
0.06= mass/density.
0.06 x density = mass.
0.06 x 1000 = mass.
Mass of the man = 60kg.
(3)
Ashish said:
1 decade ago
Simple density is mass per unit vol.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
Suneel_kushawaha said:
4 years ago
Inside the water pressure = Ïgh;
And force = pressure X Area. that is equal to the weight of the man.
So, Mg = Ïghlb.
=>M= Ïhlb.
And force = pressure X Area. that is equal to the weight of the man.
So, Mg = Ïghlb.
=>M= Ïhlb.
Vivek said:
5 years ago
Vol of ship = Weight of Man + Vol of Ship after shink.
LxBxH = M + LxBx (H-1).
Can't it be done like this? Please tell me.
LxBxH = M + LxBx (H-1).
Can't it be done like this? Please tell me.
Pratik said:
3 years ago
In ship stability,
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
(2)
Megathesh said:
6 months ago
1 cm =0.01 m.
So, that 1 cm is converted into a meter because of the length and breadth are in metre.
So, that 1 cm is converted into a meter because of the length and breadth are in metre.
(1)
SVK said:
1 decade ago
@Hannan.
Density of H2O IS 1000kg/m3.
Google density of water and it gives you 1000kg/m3.
Density of H2O IS 1000kg/m3.
Google density of water and it gives you 1000kg/m3.
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