Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
33 comments Page 2 of 4.
Priya said:
7 years ago
By using the concept of buoyancy I couldn't understand.
Please help me, @Mihir Jha.
Please help me, @Mihir Jha.
Aashritha said:
1 decade ago
What is the formula used in calculating the volume of water displaced l*b*h, If so?
Gurpreet said:
1 decade ago
Why did we take volume of water displaced here?
How density of water calculated?
How density of water calculated?
Bhuvi said:
5 years ago
The density of water is unity. And 1 cm when converted to m it becomes 0. 01m.
Hannan said:
1 decade ago
How density of water is measured? Can anybody help me please.
Suhaas said:
9 years ago
How volume of water displaced is equal to the mass of a man?
Mrinal said:
1 decade ago
The height is given 1cm when it sinks, so H is 0.01m.
Sri said:
4 years ago
The Default value of water density is 1000Kg/m3.
(1)
Haritha said:
1 decade ago
Why did we take volume of water displaced here?
Sanket kapse said:
5 years ago
How the Density is 1000? Please explain me.
(2)
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