Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
33 comments Page 2 of 4.
Aashritha said:
1 decade ago
What is the formula used in calculating the volume of water displaced l*b*h, If so?
Moses said:
1 decade ago
Guys, remember from the question, the man sat on the boat and the boat was floating meaning that his weight is equal to the weight of the fluid displaced (Archimedes principle).
But Density = Mass/Volume. Make mass the subject you get.
Mass of water displaced = Volume of water displaced x Density of water.
So from the above explanation, Mass of the man = Mass of water displaced.
Hence Mass of man = Volume of water displaced x Density of water.
But Density = Mass/Volume. Make mass the subject you get.
Mass of water displaced = Volume of water displaced x Density of water.
So from the above explanation, Mass of the man = Mass of water displaced.
Hence Mass of man = Volume of water displaced x Density of water.
Ashish said:
1 decade ago
Simple density is mass per unit vol.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
Density of water is 1000 kg/m^3 is always CONSTANT.
Volume is calculated from given parameters l*b*h.
Therefore density = (mass/volume).
Mass = (density*volume).
Mass = (1000/(l*b*h)).
Ans = 1000*0.06.
Suhaas said:
9 years ago
How volume of water displaced is equal to the mass of a man?
Aliza mir said:
9 years ago
@Suhaas, via the Archimedes principle.
Varun said:
9 years ago
How volume of water is taken as l*b*h?
Latha said:
9 years ago
It is solved by using Archimedes principle.
Mihir jha said:
9 years ago
Hi friends, we can do this sum by applying the concept of buoyancy.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Increase in weight =Inc in buoyant force.
Therefore,Mg = vdg,
M = vd,
M = (2 * 3 * 0.01)m * 1000,
(Vol. Of water displaced * density of water).
Thus mass of the man is 60 kg.
Kapil said:
8 years ago
Why not the mass is 72kg?
Skd said:
8 years ago
Please define 0.01 where it comes from?
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