Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 6)
6.
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Answer: Option
Explanation:
| Volume of water displaced | = (3 x 2 x 0.01) m3 |
| = 0.06 m3. |
 Mass of man |
= Volume of water displaced x Density of water |
| = (0.06 x 1000) kg | |
| = 60 kg. |
Discussion:
33 comments Page 4 of 4.
Pratik said:
3 years ago
In ship stability,
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
Displacement of the ship (mass of ship) = under water volume of the ship - density of water.
(2)
Keenly said:
3 years ago
From where 0.01 came? Please explain me.
Megathesh said:
7 months ago
1 cm =0.01 m.
So, that 1 cm is converted into a meter because of the length and breadth are in metre.
So, that 1 cm is converted into a meter because of the length and breadth are in metre.
(1)
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