Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 4 of 7.
Swapna said:
9 years ago
Can anyone know the shortcut method to solve this problem?
Moni said:
9 years ago
A can do a work in P days and B can do the same work in 2P days, A stop working after some days B alone complete the work in R days. How many days it takes to complete the work?
Can anyone solve this problem?
Can anyone solve this problem?
Ashok said:
9 years ago
Verification of answers:
B can do 10 days work in = 10/15.
A can do one day work = 1/18.
So we can verify the options like to became A+B = 1.
Given That,
B left the work after days so.
10/15+ x*1/18 = 1.
By verifying result: x = 6.
B can do 10 days work in = 10/15.
A can do one day work = 1/18.
So we can verify the options like to became A+B = 1.
Given That,
B left the work after days so.
10/15+ x*1/18 = 1.
By verifying result: x = 6.
SHRAVAN LAL said:
10 years ago
A ----- 18 days * 5
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
Arsh said:
10 years ago
{(1/15)*10}+{(1/18)*x} = 1.
x = 6.
x = 6.
Mudasir Ali said:
10 years ago
Let total work be x. A completes in 15 days i.e in 15 days:
x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15 = x.
In each day A does x/15 of work.
x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15 = x.
In each day A does x/15 of work.
Sunil Singh said:
10 years ago
@Willoy.
Here B is alone working for 10 days without the help of A.
So work done by B in 10 days = 10*1/15 = 2/3.
Remaining work after 10 days 1-2/3 = 1/3.
Here B is alone working for 10 days without the help of A.
So work done by B in 10 days = 10*1/15 = 2/3.
Remaining work after 10 days 1-2/3 = 1/3.
Kullu sandhu fdk punjab said:
10 years ago
Hi friend see here:
{Time taken to complete work = Left work*Time taken to complete full work}.
Left work 1/3.
Time taken to complete full work by a = 8 then 1/3*8 = 6 answer.
{Time taken to complete work = Left work*Time taken to complete full work}.
Left work 1/3.
Time taken to complete full work by a = 8 then 1/3*8 = 6 answer.
Musheer said:
1 decade ago
Look 1 work is done in 18 days. So 1/3 work is done in 18*(1/3).
Hope its clear.
Hope its clear.
Gobinath b said:
1 decade ago
Anyone can you how it is?
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