Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 3 of 7.
Rohit said:
7 years ago
[A's 1day work = 1/18.
In how many days(x) =1/3 of total work.]
Cross multiplication:
1*1/3=1/18*x
X=6 days.
In how many days(x) =1/3 of total work.]
Cross multiplication:
1*1/3=1/18*x
X=6 days.
GHULE ARUN said:
8 years ago
@Ankush
Here is answer for your question.
Take LCM of 36, 42 & 48 i.e. 1008
Now Rehman and Sandeep star work and worked for 6 days.
Now per day work of Rehman = 1008/36 = 28
And per day work of Sandeep = 1008/42=24
Together they have completed per day work = 28+24=52.
Now in 6 days, they completed 52*6 = 312 work out of 1008.
Now last 10 days again Rehman and Sandeep worked so the work completed in 10 days = 52*10=520.
So total work completed by Rehman and Sandeep = 312+520=832.
Remaining work = 1008-832= 176 which is completed by Abbas alone and Abbas per day work is 1008/48= 21.
So Abbas worked for 176/21 Days. Or 8 8/21 days.
Here is answer for your question.
Take LCM of 36, 42 & 48 i.e. 1008
Now Rehman and Sandeep star work and worked for 6 days.
Now per day work of Rehman = 1008/36 = 28
And per day work of Sandeep = 1008/42=24
Together they have completed per day work = 28+24=52.
Now in 6 days, they completed 52*6 = 312 work out of 1008.
Now last 10 days again Rehman and Sandeep worked so the work completed in 10 days = 52*10=520.
So total work completed by Rehman and Sandeep = 312+520=832.
Remaining work = 1008-832= 176 which is completed by Abbas alone and Abbas per day work is 1008/48= 21.
So Abbas worked for 176/21 Days. Or 8 8/21 days.
Santhiya' said:
8 years ago
Good explanation. Thank you all.
Ranjit said:
8 years ago
X/18 +10/15 =1.
X+12 = 18,
X = 18 - 12,
= 6 days.
X+12 = 18,
X = 18 - 12,
= 6 days.
@ankushforbank said:
8 years ago
Rahman Sandeep and Abass can complete a work in 36, 42 and 48 days respectively. Rahman and Sandeep start the work after 6 days they take a leave for few days and handed the work to Abaas. Rahman and Sandeep leave ends 10 days before the work complete and Abass leaves the work on the return of Rahman and Sandeep. Find for how many days Abaas work?
Can anyone solve this time and work problem?
Can anyone solve this time and work problem?
Shehnaz khatun said:
9 years ago
B + S can do 1 work in 8 days.
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
Kamlesh said:
9 years ago
I did not understand the solution. Can someone please explain in step by step?
Tani said:
9 years ago
Two men can do a piece of work in 6 hours and 4 hours. After the first has worked for 2 hours he is joined by another man. By when should the work be completed?
Can anyone please solve this question. I am facing a lot of problem in this question. This is from composite mathematics. The answer at the back is 1 hour 36 minutes and I am getting 1 hour 33 Minutes.
Can anyone please solve this question. I am facing a lot of problem in this question. This is from composite mathematics. The answer at the back is 1 hour 36 minutes and I am getting 1 hour 33 Minutes.
Sowndarya said:
9 years ago
Simple & super @Arsh.
Akshay silgari said:
9 years ago
I don't understand the logic of multiplying 18*1/3. Please help me in this.
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