Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 1 of 7.
Malliga said:
1 decade ago
I can't understand.
Jay said:
1 decade ago
See, B complete his work in 15 days so split in 3 so we get 1:1:1.
Then he done the work of 10 days, so only last one remaining.1/3.
Now, A finish the whole work in 1/18. He need to done work in 1/3.
So 18*1/3 = 6 days.
Then he done the work of 10 days, so only last one remaining.1/3.
Now, A finish the whole work in 1/18. He need to done work in 1/3.
So 18*1/3 = 6 days.
UDAY.H.P said:
1 decade ago
Consider the full work to be done = 1
A can complete his work in 15 days but at the same speed he will work only for 10 days that is = 2/3
then the remaining work is = 1-(2/3)
A's working speed is =1/18 per day
that means aA can compleate this total work in 18 day
but the remaining work is 1/3 so 1/3*18 that is=6days
A can complete his work in 15 days but at the same speed he will work only for 10 days that is = 2/3
then the remaining work is = 1-(2/3)
A's working speed is =1/18 per day
that means aA can compleate this total work in 18 day
but the remaining work is 1/3 so 1/3*18 that is=6days
Siva said:
1 decade ago
Hi Guys,
A can complete work in 18 days
A's 1 day work = 1/18--------------(1)
B can complete work in 15 Days
B's 1 day work = 1/15--------------(2)
[but B is working 10 days only]
Remaining work is 5 days
so, remaining 1 day work is 5*(1/15) =>1/3
A's 1/3 work can complete in N days
so A's 1 day work = 1/3N--------------(3)
Equation=> (2)=(3)
1/3N = 1/18
so, N = 18/3
N = 6 Days
A's (1/3) remaining work can complete in 6 Days
N = 6 Days
A can complete work in 18 days
A's 1 day work = 1/18--------------(1)
B can complete work in 15 Days
B's 1 day work = 1/15--------------(2)
[but B is working 10 days only]
Remaining work is 5 days
so, remaining 1 day work is 5*(1/15) =>1/3
A's 1/3 work can complete in N days
so A's 1 day work = 1/3N--------------(3)
Equation=> (2)=(3)
1/3N = 1/18
so, N = 18/3
N = 6 Days
A's (1/3) remaining work can complete in 6 Days
N = 6 Days
Gayu said:
1 decade ago
Superb siva.
Kusum said:
1 decade ago
Can anyone explain this 1/3*18 ? please.
Md Ali Umar said:
1 decade ago
Hi @Kusum...........
We have to find how many days have to work to A for finishing the the remaining work. remaining work is 1/3
so we know the processes
. .
. A finishes 1/18 work in 1 day
.
. . ,, ,, 1 ,, ,, 1/(1/18) day
.
. . ,, ,, 1/3 ,, ,,1*(18/1)*(1/3)
After solving you well get 6days answer.
Understand???????????
We have to find how many days have to work to A for finishing the the remaining work. remaining work is 1/3
so we know the processes
. .
. A finishes 1/18 work in 1 day
.
. . ,, ,, 1 ,, ,, 1/(1/18) day
.
. . ,, ,, 1/3 ,, ,,1*(18/1)*(1/3)
After solving you well get 6days answer.
Understand???????????
Ramkumar said:
1 decade ago
L.C.M=90
b one day capacity is 6
a one day capacity is 5
b work done in 10 days,then 6*10=60
total work(L.C.M)=90-60=30
now,30/a capacity
30/5
=6
b one day capacity is 6
a one day capacity is 5
b work done in 10 days,then 6*10=60
total work(L.C.M)=90-60=30
now,30/a capacity
30/5
=6
(1)
Anusha said:
1 decade ago
A's 1day work = 1/18
B's 1 day work =1/15
but B left the job after 10 days so it is = 10/15
let no of days A alone should work be x
10/15+x/18=1
x/18=1-10/15
x/18=5/15
x/18=1/3
cross mulitiply
x=18/3
x=6
B's 1 day work =1/15
but B left the job after 10 days so it is = 10/15
let no of days A alone should work be x
10/15+x/18=1
x/18=1-10/15
x/18=5/15
x/18=1/3
cross mulitiply
x=18/3
x=6
Bala said:
1 decade ago
Answer explained
A's one day work =1/18
B's one day work =1/15
So B worked for 10 days to do a work 1
So B's 10 day work =(1/15)*10 = 10/15 =2/3
B worked only 10 days to complete a work (i.e)1
Therefore remaining work is 1-2/3 =1/3
Now the remaining work is to be completed by A
A's 1 day work is 1/18
To complete 1/3 of work A takes= 1/18*3 = 1/6
Ans 6
A's one day work =1/18
B's one day work =1/15
So B worked for 10 days to do a work 1
So B's 10 day work =(1/15)*10 = 10/15 =2/3
B worked only 10 days to complete a work (i.e)1
Therefore remaining work is 1-2/3 =1/3
Now the remaining work is to be completed by A
A's 1 day work is 1/18
To complete 1/3 of work A takes= 1/18*3 = 1/6
Ans 6
(1)
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