Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 2 of 7.
Shro said:
1 decade ago
@Siva if you got answer as 5 by subtracting 1/15 - 1/10, then its wrong as this subtraction will get different answer.
Amit said:
1 decade ago
See ;
B can work 1/15 part of the work in one day and he has worked 10 days means - 1/15*10 = 2/3 part of work has been completed. Hence remained work is 1-2/3 = 1/3.
Given,
A can complete whole work in 18 days.
Hence,
1/3 part of work will be completed in 18*1/3 = 6 days.
B can work 1/15 part of the work in one day and he has worked 10 days means - 1/15*10 = 2/3 part of work has been completed. Hence remained work is 1-2/3 = 1/3.
Given,
A can complete whole work in 18 days.
Hence,
1/3 part of work will be completed in 18*1/3 = 6 days.
Kavya said:
1 decade ago
There's easy method:
Given for A:18, for B:15.
-10 days = 5 days.
Therefore (5/15) 18 = 6 days.
Given for A:18, for B:15.
-10 days = 5 days.
Therefore (5/15) 18 = 6 days.
Meher said:
1 decade ago
I don't understand the logic of multiplying 18*1/3.
Swapnika said:
1 decade ago
A done in 18 says so we can do in this way also:
18*5 //therefore (15-10=5).
18*5 = 90.
90/15 = 6.
18*5 //therefore (15-10=5).
18*5 = 90.
90/15 = 6.
Ruchi Jain said:
1 decade ago
Well the way I solve this question,
REMAINING IS 30 which is to be done by A and A's rate is 5 30/5 = 6.
A B B
T 18 15 10
R 5 6 6
W 90 90 60
REMAINING IS 30 which is to be done by A and A's rate is 5 30/5 = 6.
Ajay Singh said:
1 decade ago
See as per my knowledge of solving such question it should be in this way:
A's 1 day work=1/18,
B's 1 day work=1/15,
Both (A+B)'s 1 day work =1/18+1/15=1/10,
So their 10 days of work together will be=1/10*10=1,
Thus,remaining work =1-1=0,
So, in my opinion this question is incorrect.
Please reply if I am wrong and give possible solution.
A's 1 day work=1/18,
B's 1 day work=1/15,
Both (A+B)'s 1 day work =1/18+1/15=1/10,
So their 10 days of work together will be=1/10*10=1,
Thus,remaining work =1-1=0,
So, in my opinion this question is incorrect.
Please reply if I am wrong and give possible solution.
Raja said:
1 decade ago
LCM 90 brief explain?
Left the job B what mean?
Left the job B what mean?
Deepak Patgar said:
1 decade ago
It will be easy if we use chocolate method.
A takes 18 days and B takes 15 days. LCM of 18 and 15 is 90.
Let 90 be the total number of chocolates.
A takes 18 days to eat 90 chocolates. so A eats 5 chocolates per day.
B takes 15 days to eat 90 chocolates. So B eats 6 chocolates per day.
in 10 days B finishes 6*10 = 60 chocolates.
Remaining chocolates are 30.
So to eat 30 chocolates A need 30/5 = 6 days.
Ans = 6 days.
A takes 18 days and B takes 15 days. LCM of 18 and 15 is 90.
Let 90 be the total number of chocolates.
A takes 18 days to eat 90 chocolates. so A eats 5 chocolates per day.
B takes 15 days to eat 90 chocolates. So B eats 6 chocolates per day.
in 10 days B finishes 6*10 = 60 chocolates.
Remaining chocolates are 30.
So to eat 30 chocolates A need 30/5 = 6 days.
Ans = 6 days.
Sayali said:
1 decade ago
@Rucha.
How you calculate that rate?
How you calculate that rate?
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