Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 7 of 7.
UDAY.H.P said:
1 decade ago
Consider the full work to be done = 1
A can complete his work in 15 days but at the same speed he will work only for 10 days that is = 2/3
then the remaining work is = 1-(2/3)
A's working speed is =1/18 per day
that means aA can compleate this total work in 18 day
but the remaining work is 1/3 so 1/3*18 that is=6days
A can complete his work in 15 days but at the same speed he will work only for 10 days that is = 2/3
then the remaining work is = 1-(2/3)
A's working speed is =1/18 per day
that means aA can compleate this total work in 18 day
but the remaining work is 1/3 so 1/3*18 that is=6days
Jay said:
1 decade ago
See, B complete his work in 15 days so split in 3 so we get 1:1:1.
Then he done the work of 10 days, so only last one remaining.1/3.
Now, A finish the whole work in 1/18. He need to done work in 1/3.
So 18*1/3 = 6 days.
Then he done the work of 10 days, so only last one remaining.1/3.
Now, A finish the whole work in 1/18. He need to done work in 1/3.
So 18*1/3 = 6 days.
Malliga said:
1 decade ago
I can't understand.
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