Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 5)
5.
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Answer: Option
Explanation:
| C's 1 day's work = | 1 | - |  |
1 | + | 1 |  |
= | 1 | - | 7 | = | 1 | . |
| 3 | 6 | 8 | 3 | 24 | 24 |
| A's wages : B's wages : C's wages = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
| 6 | 8 | 24 |
 C's share (for 3 days) = Rs. |
|
3 x | 1 | x 3200 | |
= Rs. 400. |
| 24 |
Discussion:
179 comments Page 4 of 18.
Rajat Kumar Pal said:
7 years ago
Assume W=24 unit because multiple of 6 and 8 days.
A- 6days - 24/6=4u/d
B- 8 Days - 24/8=3u/d
C-?
A&B&C=24/3=8u/d.
So, C= 1u/d because A&B&C take 8u/d so subtract the total minus - individual A and B.
Pa: Pb: Pc = Wa: Wb: Wc
=Ra: Rb: Rc.
so Rc=3*1/24*3200=400.
A- 6days - 24/6=4u/d
B- 8 Days - 24/8=3u/d
C-?
A&B&C=24/3=8u/d.
So, C= 1u/d because A&B&C take 8u/d so subtract the total minus - individual A and B.
Pa: Pb: Pc = Wa: Wb: Wc
=Ra: Rb: Rc.
so Rc=3*1/24*3200=400.
Joel said:
4 years ago
A's one day work = 1/6,
B's one day work = 1/8,
A's 3 days wages = 3 days * 1/6 work per day * 3200rs i.e.,3 * (1/6) * 3200 = 1600rs
B's 3 days wages = 3 days * 1/8 work per day * 3200rs i.e.,3 * (1/8) * 3200 = 1200rs.
Now remaining money is 3200-(1600+1200) = 400rs is C's 3 days wages.
B's one day work = 1/8,
A's 3 days wages = 3 days * 1/6 work per day * 3200rs i.e.,3 * (1/6) * 3200 = 1600rs
B's 3 days wages = 3 days * 1/8 work per day * 3200rs i.e.,3 * (1/8) * 3200 = 1200rs.
Now remaining money is 3200-(1600+1200) = 400rs is C's 3 days wages.
(21)
Mouni said:
1 decade ago
Hi @Danish.
In sum we have total work of a, b, c so we subtract both a and b work from total work then we will get c work that is 1/24 ok.
And then to find ratio of wages we multiply with 24 why because the LCM of a, b, c is 24. So we multiply with 24 and get ratios of all.
In sum we have total work of a, b, c so we subtract both a and b work from total work then we will get c work that is 1/24 ok.
And then to find ratio of wages we multiply with 24 why because the LCM of a, b, c is 24. So we multiply with 24 and get ratios of all.
K appala naidu said:
9 years ago
A's one day work = 1/6
B's one day work= 1/8
C's one day work = 1/x
A + B + C one day work = 1/3.
1/6 + 1/8 + 1/x = 1/3.
C's one day work is 1/24.
The ratio of A : B : C is 1/6 : 1/8 : 1/24 = 4 : 3 : 1.
For 8 parts 3200 for C's 1 part 3200/8 = 400. So, the answer is 400.
B's one day work= 1/8
C's one day work = 1/x
A + B + C one day work = 1/3.
1/6 + 1/8 + 1/x = 1/3.
C's one day work is 1/24.
The ratio of A : B : C is 1/6 : 1/8 : 1/24 = 4 : 3 : 1.
For 8 parts 3200 for C's 1 part 3200/8 = 400. So, the answer is 400.
Sruthi said:
7 years ago
The total work-> 24 {LCM of days}.
A's 1day work->4,
B's 1day work->3,
with the help of C they completed the work in 3 days,
A+B+C=8 {24/3 ie, total work/no.of days to complete}.
4+3+C=8.
C=1.
Then, 3200/8=400.
C does 1unit so C gets 400.
If it does 2units 400 * 2.
A's 1day work->4,
B's 1day work->3,
with the help of C they completed the work in 3 days,
A+B+C=8 {24/3 ie, total work/no.of days to complete}.
4+3+C=8.
C=1.
Then, 3200/8=400.
C does 1unit so C gets 400.
If it does 2units 400 * 2.
(1)
Pritam said:
3 years ago
Its too easy.
A can do a job in 6 days: A=6.
B can do a job in 8 days: B=8.
6&8 LCM is 24.
Now, 6 * 4 = 24(A). 8 * 3 = 24(B).
A + B + C = 3Days, 3 * 8 = 24(A+B+C).
If ABC= 8 and A is 4 And B is 3.
So, (4-3 = 1:C) : C= 1.
Now ratio will be 4:3:1.
And C =400.
A can do a job in 6 days: A=6.
B can do a job in 8 days: B=8.
6&8 LCM is 24.
Now, 6 * 4 = 24(A). 8 * 3 = 24(B).
A + B + C = 3Days, 3 * 8 = 24(A+B+C).
If ABC= 8 and A is 4 And B is 3.
So, (4-3 = 1:C) : C= 1.
Now ratio will be 4:3:1.
And C =400.
(25)
Avinash said:
3 years ago
@All
Here, we have to find C's 1day work.
A's1day + B's1day + C's1day = total work done in one day for 3 days by A+B+C.
= 1/6 + 1/8 + C = 1/3.
(1/6+1/8) + C = 1/3.
(7/24)+C = 1/3.
Therefore, C= 1/3-7/24.
C=1/24.
Am I right? Please clarify me.
Here, we have to find C's 1day work.
A's1day + B's1day + C's1day = total work done in one day for 3 days by A+B+C.
= 1/6 + 1/8 + C = 1/3.
(1/6+1/8) + C = 1/3.
(7/24)+C = 1/3.
Therefore, C= 1/3-7/24.
C=1/24.
Am I right? Please clarify me.
(43)
Vinnu said:
1 decade ago
See from the problem we can calculate c's 1 day work = 1/24.
It means he can complete work in 24 days.
So for calculating wage of c we can say for 24 days he is to be paid 3200. But for 3 days he is to be paid?
Cross multiply we get (3*3200) /24=400.
Its easy.
It means he can complete work in 24 days.
So for calculating wage of c we can say for 24 days he is to be paid 3200. But for 3 days he is to be paid?
Cross multiply we get (3*3200) /24=400.
Its easy.
Rahul Manjhi said:
8 years ago
If A do work in 6days then in 3days the amount he will get=3/6*3200=1600.
If B do work in 8days then in 3days the amount he will get=3/8*3200=800.
Therefore,1600+800(A+B)took together=2800.
Now, total amount=3200.
So the amount C will get=3200-2800=400(answer).
If B do work in 8days then in 3days the amount he will get=3/8*3200=800.
Therefore,1600+800(A+B)took together=2800.
Now, total amount=3200.
So the amount C will get=3200-2800=400(answer).
Aya adel said:
2 years ago
if a &b end the job they take 3200.
a = 1/6.
b = 1/8.
a+b+c = 1/3.
1/6 + 1/8 + 1/c = 1/3.
1/c = 1/3 - 7/24.
1/c = 1/24.
if c works for 24/24 days it will take 3200.
but it works for 3 days 3/24.
So 3200*3/24 divided by 24/24.
Then answer is 400.
a = 1/6.
b = 1/8.
a+b+c = 1/3.
1/6 + 1/8 + 1/c = 1/3.
1/c = 1/3 - 7/24.
1/c = 1/24.
if c works for 24/24 days it will take 3200.
but it works for 3 days 3/24.
So 3200*3/24 divided by 24/24.
Then answer is 400.
(46)
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