Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
289 comments Page 3 of 29.
D venkat raman said:
3 years ago
A is thrice as good as workman as B and therefore can finish a job in 60 days - question
Just think A thrice is 90;
How means;
A is thrice as b;
For A assume as x;
then B assume as 2x;
then C assume as 3x;
in question they thrice -- so we can assume thrice as 3x;
if one is 30 means.
then twice as 60.
then thrice as 90.
So , one day of the work is 1/30, then thrice day of the work is 1/90.
Working together A+B;
1/30+1/90;then.
Then take lcm it will give 90.
Then check whether the 90 is in a and b
3+1/90;
4/90;
2/45;
Then reciprocal it or div it will give 22 1/2.
Just think A thrice is 90;
How means;
A is thrice as b;
For A assume as x;
then B assume as 2x;
then C assume as 3x;
in question they thrice -- so we can assume thrice as 3x;
if one is 30 means.
then twice as 60.
then thrice as 90.
So , one day of the work is 1/30, then thrice day of the work is 1/90.
Working together A+B;
1/30+1/90;then.
Then take lcm it will give 90.
Then check whether the 90 is in a and b
3+1/90;
4/90;
2/45;
Then reciprocal it or div it will give 22 1/2.
(20)
Mishra said:
10 months ago
Given: A takes 60 days less than B.
So, let A takes 90days,
B takes 30days.
LCM of 90, 30 = 180 and effeciency of A = 2 (180/90), B = 6 (180/30);
Both work together A + B = (2+6) = 8;
So, total work = 180(LCM);
total days = work/efficiency of both.
= 180/8 = 22.5.
So, let A takes 90days,
B takes 30days.
LCM of 90, 30 = 180 and effeciency of A = 2 (180/90), B = 6 (180/30);
Both work together A + B = (2+6) = 8;
So, total work = 180(LCM);
total days = work/efficiency of both.
= 180/8 = 22.5.
(16)
Jagadish Behera said:
4 years ago
"A" is 3 times more than" B" (efficiency)
Difference = 60 days
3x-x = 60
X = 30days This is" B"
A=3 * 30 = 90 days.
So Total work =180
A=2 WORK
B=6 WORK
A+B TOGETHER CAN DO IN 180/8 = 22.5 DAYS.
Difference = 60 days
3x-x = 60
X = 30days This is" B"
A=3 * 30 = 90 days.
So Total work =180
A=2 WORK
B=6 WORK
A+B TOGETHER CAN DO IN 180/8 = 22.5 DAYS.
(14)
Yash Sangle said:
12 months ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
so, B = 90, A = 30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
As work done and time are inversely related,
so, B = 90, A = 30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
(13)
Muhammad said:
5 years ago
Let A's total work completion time be = n.
B's total work completion time = 3n,
Difference between B and A's daily work = 60.
3n - n = 60,
2n = 60.
n = 30.
Total daily work.
=1/3n + 1/n,
=1/90 + 1/30,
=2/45,
So total time to complete for both = 45/2 = 22.5.
B's total work completion time = 3n,
Difference between B and A's daily work = 60.
3n - n = 60,
2n = 60.
n = 30.
Total daily work.
=1/3n + 1/n,
=1/90 + 1/30,
=2/45,
So total time to complete for both = 45/2 = 22.5.
(12)
Logesh said:
2 years ago
Finding the days for B and A:
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
(10)
Gogo said:
4 years ago
A+B = (1/30 + 1/90) = 2/45.
How we are getting this?
How we are getting this?
(8)
Nallapu Rishith Reddy said:
1 year ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
so, B=90, A=30.
(1/90+1/30)=(2/45),
So, 22 1/5.
As work done and time are inversely related,
so, B=90, A=30.
(1/90+1/30)=(2/45),
So, 22 1/5.
(5)
Yash Sangle said:
12 months ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
So, B=90, A=30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
As work done and time are inversely related,
So, B=90, A=30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
(5)
Astik Mandal said:
5 years ago
A - 30d.
B - 90d.
lcm - 90(total work).
Efficiency of A - 3.
Efficiency of B - 1.
Total Efficiency = 4 total.
work/totalEfficiency=90/4=22.5.
B - 90d.
lcm - 90(total work).
Efficiency of A - 3.
Efficiency of B - 1.
Total Efficiency = 4 total.
work/totalEfficiency=90/4=22.5.
(4)
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