Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
281 comments Page 1 of 29.
Dhananjay said:
3 years ago
3x-x = 60,
x = 30.
A=90 B=30.
LCM(90,30) == 90unit.
for A -------> 1unit/day.
for B ------->3unit/day.
Total unit of work = 90/4 = 22.5.
x = 30.
A=90 B=30.
LCM(90,30) == 90unit.
for A -------> 1unit/day.
for B ------->3unit/day.
Total unit of work = 90/4 = 22.5.
(146)
SIBAJI MALLIK said:
2 years ago
A : B
1 : 3.
Difference = 2.
i.e 2 part = 60 (given),
1 part= 60/2 = 30.
A can do it in 30 days.
B can do it in 90 days.
A's 1 day's work= 1/30 and,
B's 1 day's work= 1/90,
A+B 1 day's work = 1/30 + 1/90 = 2/45.
They can do it in 45/2 days.
1 : 3.
Difference = 2.
i.e 2 part = 60 (given),
1 part= 60/2 = 30.
A can do it in 30 days.
B can do it in 90 days.
A's 1 day's work= 1/30 and,
B's 1 day's work= 1/90,
A+B 1 day's work = 1/30 + 1/90 = 2/45.
They can do it in 45/2 days.
(108)
Vpk said:
2 years ago
A B
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(103)
Taukir said:
9 months ago
A takes time = x days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
(84)
Furquan Shiekh said:
10 months ago
Suppose A takes x days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
(73)
Suhas Wankhede said:
2 years ago
Given Equation
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
(64)
Aya adel said:
2 years ago
a : b
1 : 3.
And x-60:x
Then 3(x - 60) = x.
3x-180 = x,
2x = 180,
x = 90.
a = 90 - 60 = 30
b = 90
1\a + 1\b = 1\30 + 1\90 = 2\45.
a + b = 45\2.
So, the answer is 22 1\2.
1 : 3.
And x-60:x
Then 3(x - 60) = x.
3x-180 = x,
2x = 180,
x = 90.
a = 90 - 60 = 30
b = 90
1\a + 1\b = 1\30 + 1\90 = 2\45.
a + b = 45\2.
So, the answer is 22 1\2.
(57)
Harsha said:
2 years ago
A takes x-60 days.
B takes x days.
If A does work in 1 day then B takes 3 days.
So,
1/(x-60) = 1/x
Solving this we get x = 90
Now, A+B can do work in 1/90 + 3/90.
We get 45/2.
B takes x days.
If A does work in 1 day then B takes 3 days.
So,
1/(x-60) = 1/x
Solving this we get x = 90
Now, A+B can do work in 1/90 + 3/90.
We get 45/2.
(49)
Man said:
3 years ago
Given A:B = 1:3 => B = 3A.'
Let assume A can complete work in x days which implies B = 3x
and also given B-A = 60 => 3x-x = 60 => 2x = 60 => x = (60/2) => 30
therefore A can complete the work in 30 days. and B can complete the work in 3*30 = 90 days
1 day work of A & B together = 1/30 + 1/90 = 4/90.
If they both do 4/90 work in one day so to complete the whole 1 work they will take;
(4/90) * x = 1.
x = 90/4 = 45/2 = 22 1/2.
Let assume A can complete work in x days which implies B = 3x
and also given B-A = 60 => 3x-x = 60 => 2x = 60 => x = (60/2) => 30
therefore A can complete the work in 30 days. and B can complete the work in 3*30 = 90 days
1 day work of A & B together = 1/30 + 1/90 = 4/90.
If they both do 4/90 work in one day so to complete the whole 1 work they will take;
(4/90) * x = 1.
x = 90/4 = 45/2 = 22 1/2.
(47)
Nikita raisadhar said:
5 months ago
3x - x=60
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
(46)
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