Aptitude - Time and Work - Discussion

Let A complete work in = x days.
B will complete work in = 3x days.

(As a is 3x sufficient so b will take 3x much time)
Also, A take 60 days less,
So days were taken by B - 60 = days taken by A
So equation will be;
3x - 60 = x,
2x = 60,
x = 30.

So A completes work in 30 days and B in 30 X x = 90
A 1-day work = 1/30,
B 1 day work = 1/90,

1 day work of A & B together = 1/30 + 1/90 = 4/90.

If they both do 4/90 work in one day so to complete the whole 1 work they will take
4/90 X x = 1.
x = 90/4 = 45/2 = 22 1/2.

As A is thrice good than B then the Ratio of work done together is:

A : B
3 : 1

As A do work 60 days less than B , Suppose;
A : B
30 : 90---->LCM = 90,
(30×3)----->3u of A+1u of B =4u,
I.e 90/4 = 45/2 = 22(1/2).

A is thrice as good as workman as B and therefore can finish a job in 60 days less than B. Working together, they can do it in:

A = 3x, B= 1x ----> {1}
Here A's efficiency = 3.
B's efficiency = 1.

The Sum of their efficiency is 4 (we will need this later on).

According to the question:
A = 3x - 60.

Therefore 1 day's work of A and B is:
1/(3x-60) = 1/(x).
By solving we get x = 30
By putting the value of x in eqn {1}
We get A= 3 X 30 = 90 days.
B = 30 days.

By working together, they can do it in:
90/4 days.
By further solving, we get 22 1/2 days.

Given;

A = 3B;
A = B - 60.

Substitute A = 3B in 2nd equation(a=b-60).
3B = B-60
B = 30.

Therefore; A = 3B = 90.

A+B = (1/30 + 1/90) = 2/45.
So, the answer is 22(1/2).

A is thrice as good as workman as B and therefore can finish a job in 60 days - question
Just think A thrice is 90;
How means;

A is thrice as b;
For A assume as x;
then B assume as 2x;
then C assume as 3x;

in question they thrice -- so we can assume thrice as 3x;
if one is 30 means.
then twice as 60.
then thrice as 90.
So , one day of the work is 1/30, then thrice day of the work is 1/90.

Working together A+B;
1/30+1/90;then.
Then take lcm it will give 90.
Then check whether the 90 is in a and b
3+1/90;
4/90;
2/45;
Then reciprocal it or div it will give 22 1/2.

Assume B can do it in x days.
So A can in x/3 days.
x - x/3 = 60.
then x = 90.
So B can do the work in 90 days.
A can do it in 90/3 = 30 days.
A and B together can do it in 90 * 30/90 + 30 = 22.5 (Ans).

"A" is 3 times more than" B" (efficiency)

Difference = 60 days

3x-x = 60

X = 30days This is" B"

A=3 * 30 = 90 days.

So Total work =180

A=2 WORK
B=6 WORK

A+B TOGETHER CAN DO IN 180/8 = 22.5 DAYS.

Let A's total work completion time be = n.
B's total work completion time = 3n,
Difference between B and A's daily work = 60.
3n - n = 60,
2n = 60.
n = 30.

Total daily work.
=1/3n + 1/n,
=1/90 + 1/30,
=2/45,
So total time to complete for both = 45/2 = 22.5.

Finding the days for B and A:

The ratio difference is 2 and the day difference is 60.

So, for every single inc in ratio, it will increase by 30 days.

From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).

I am not understanding this question.

Anyone help me to get it be explaining it along with the formulas?