Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
30 | 90 | 90 | 45 |
![]() |
45 | = 22 | 1 | days. |
2 | 2 |
Discussion:
281 comments Page 26 of 29.
Tachime sangma said:
6 years ago
How come 4/90? I don't understand.
Meg said:
6 years ago
First thing, the work done is always same, i.e. Work done by A = work done by B = work done by A+B.
So, if A does a work in x days then B does it in 60-x days.
Now, we can write A=3B
So, work done by A will be = 1*x = x
Work done by B will be = 3*(60-x)
As we know work done remains same then
x = (60-x)*3.
x = 45,
So, A's total time = 45.
B's total time = 60-x = 60-45 = 15.
So, now we can find the total time taken by A+B to complete the work as,
1/15 + 1/45 = 4/45.
It's one day work of A+B so reciprocal it to get the total time taken by them.
45/4 = 22.5 days
So, if A does a work in x days then B does it in 60-x days.
Now, we can write A=3B
So, work done by A will be = 1*x = x
Work done by B will be = 3*(60-x)
As we know work done remains same then
x = (60-x)*3.
x = 45,
So, A's total time = 45.
B's total time = 60-x = 60-45 = 15.
So, now we can find the total time taken by A+B to complete the work as,
1/15 + 1/45 = 4/45.
It's one day work of A+B so reciprocal it to get the total time taken by them.
45/4 = 22.5 days
Subhendu said:
6 years ago
(3-1)=2------>60
1------>30
3------->90.
1's day work for A= 1/30
1's day work for b=1/90
Both 1's day work=(1/30+1/90)
= 4/90.
Total day = 90/4.
= 22(1/2).
The answer is B.
1------>30
3------->90.
1's day work for A= 1/30
1's day work for b=1/90
Both 1's day work=(1/30+1/90)
= 4/90.
Total day = 90/4.
= 22(1/2).
The answer is B.
Neena said:
6 years ago
We can simplify it.
Assume if B worked for 90 days and
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A+B = 4/90 work.
ie, 90/4 = 22.5.
Assume if B worked for 90 days and
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A+B = 4/90 work.
ie, 90/4 = 22.5.
Yash said:
6 years ago
(T*T.D)/(T^2-1).
T-EFFICIENCY.
T.D-TIME DIFFERENCE.
So;
3*60/9-1 = 22.5.
T-EFFICIENCY.
T.D-TIME DIFFERENCE.
So;
3*60/9-1 = 22.5.
Yaswanth said:
6 years ago
Let's assume A completes its work in x days.
B completes in 3x days . since A is times efficient than B.
now, their difference is 60 days.
then, x-3x=60,
2x=60,
x=30,
A=30,B=90.
So, one days work of A and B together is A+B=1/30+1/90.
=4/90,
=2/45,
So one day work of A and B together is 2/45.
So A and B can complete the work in 45/2 days.
this equals to 22(1/2).
B completes in 3x days . since A is times efficient than B.
now, their difference is 60 days.
then, x-3x=60,
2x=60,
x=30,
A=30,B=90.
So, one days work of A and B together is A+B=1/30+1/90.
=4/90,
=2/45,
So one day work of A and B together is 2/45.
So A and B can complete the work in 45/2 days.
this equals to 22(1/2).
Sanishk said:
6 years ago
What is wrong with the below step?
A's 1-day work = 1/y.
Then, B's 1-day work = 1/3y.
Now,
A completes work before 60 days compared to B.
So,
1/y - 1/3y = 1/60
2/3y = 1/60
y = 40.
i.e., A completes in 40 days and B completes in 120 days,
Now, working together they complete in
1/A + 1/B = 1/40+ 1/120 = 1/30.
So, Together they complete in 30 days.
A's 1-day work = 1/y.
Then, B's 1-day work = 1/3y.
Now,
A completes work before 60 days compared to B.
So,
1/y - 1/3y = 1/60
2/3y = 1/60
y = 40.
i.e., A completes in 40 days and B completes in 120 days,
Now, working together they complete in
1/A + 1/B = 1/40+ 1/120 = 1/30.
So, Together they complete in 30 days.
Rohan said:
6 years ago
A and B
Work 3:1
Time 1:3
i.e. 30:90 ......multiply by 30.
And also they have given that the difference between the time taken to complete the work is 60.
Hence when A and B time to work together,
1/30+ 1/90 = 2/45,
Defer for A and B to complete the entire work they require 45/2 which is equivalent to 22 and A half-day.
Work 3:1
Time 1:3
i.e. 30:90 ......multiply by 30.
And also they have given that the difference between the time taken to complete the work is 60.
Hence when A and B time to work together,
1/30+ 1/90 = 2/45,
Defer for A and B to complete the entire work they require 45/2 which is equivalent to 22 and A half-day.
Aravind said:
6 years ago
Hi, friends, it's a bit tricky.
First, they found the time difference to do work between a and b.
Because the data we have is time difference in qn for 60 days consider.
Then. If a takes 1 day. B takes 3 days. So.
For 2 days time difference : 3 days for b
Then multiply both sides by 30 since the time difference is given
For 60 days time difference: 90 days of b.
I hope you all get it.
Then use ratio. A takes 30 days to complete work.
First, they found the time difference to do work between a and b.
Because the data we have is time difference in qn for 60 days consider.
Then. If a takes 1 day. B takes 3 days. So.
For 2 days time difference : 3 days for b
Then multiply both sides by 30 since the time difference is given
For 60 days time difference: 90 days of b.
I hope you all get it.
Then use ratio. A takes 30 days to complete work.
Dinesh said:
6 years ago
Please tell how A is working 30 days. How we calculate I don't understand.
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