Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
30 | 90 | 90 | 45 |
![]() |
45 | = 22 | 1 | days. |
2 | 2 |
Discussion:
281 comments Page 27 of 29.
Priti said:
6 years ago
***shortcut method******
D= no of days.
n= n times as fast.
D*n/n^2-1
60*3/3^2-1
180/9-1
180/8=90/4=22 1/2.
D= no of days.
n= n times as fast.
D*n/n^2-1
60*3/3^2-1
180/9-1
180/8=90/4=22 1/2.
Abhijith said:
6 years ago
Can someone provide a solution for this problem using percentages or the efficiency ration ?
MOSA said:
6 years ago
Let a did this work in X days.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
Naga said:
5 years ago
The ratio of work done by A & B= 1:3.
(Because A is thrice as good as B)
A' s work done = Less than 60 days than B.
So take B's work done = x days---(1)
Then A's work done = x-60---(2)
So, 1=x-60,
3= x.
So cross mutiply as per the ratio simplification.
x * 1= 3(x-60),
x=3x-180,
3x-x=180,
x =90.
As per (1) & (2)
B's work done = 90 days,
A's work done = 90-60 = 30 days,
(A+B)'s 1 day work done = 1/30 +1/90=4/90=2/45,
Total work done = 45/2= 22 1/2 days.
(Because A is thrice as good as B)
A' s work done = Less than 60 days than B.
So take B's work done = x days---(1)
Then A's work done = x-60---(2)
So, 1=x-60,
3= x.
So cross mutiply as per the ratio simplification.
x * 1= 3(x-60),
x=3x-180,
3x-x=180,
x =90.
As per (1) & (2)
B's work done = 90 days,
A's work done = 90-60 = 30 days,
(A+B)'s 1 day work done = 1/30 +1/90=4/90=2/45,
Total work done = 45/2= 22 1/2 days.
Bindu said:
5 years ago
3/2 *60, how come 3/2?
Billal Hossain said:
5 years ago
x : 3x.
3x - x = 60,
=> 2x = 60,
=> x = 30,
1/30 + 1/90,
= 4/90.
= 22 (1/2).
3x - x = 60,
=> 2x = 60,
=> x = 30,
1/30 + 1/90,
= 4/90.
= 22 (1/2).
Rajeesh kumar said:
5 years ago
@All.
We can easily convert it to a linear equation.
Let B requires x days and forA it is y
it is given,x = 3y.
In the same way;
X-60=Y
By solving we have 2x- 180=0 :.x=90.
and y=90 - 60 = 30.
We can easily convert it to a linear equation.
Let B requires x days and forA it is y
it is given,x = 3y.
In the same way;
X-60=Y
By solving we have 2x- 180=0 :.x=90.
and y=90 - 60 = 30.
Saurabh said:
5 years ago
time diffence = 60days.
A is 3 times better then b.
That means A will do 3 times of work in day and B will do 1 time of A's work in 1 day
difference = 2 times.
Day difference = 60
1 time difference = 60/2 = 30.
A will do the work in 30 days.
B will do a work in 3*30 = 90days.
A is 3 times better then b.
That means A will do 3 times of work in day and B will do 1 time of A's work in 1 day
difference = 2 times.
Day difference = 60
1 time difference = 60/2 = 30.
A will do the work in 30 days.
B will do a work in 3*30 = 90days.
Sagar said:
5 years ago
Thank you for very simple answer @Malleswari.
Akshay Salekar said:
5 years ago
Hi, friends.
We know that A capability to do work is 3 times of B,ok
Then the the ratio of Efficiency is A:B=3:1
And the ratio of time (days) is A:B=1:3 ...(The ratio get reverse because Efficiency and time are inversely proportional)
Now,
Time taken by A to complete work = (X) day &
Time taken by B to complete work = (X+60) day.
*We compare the ratio of time
(X/X+60)=(1/3) get X = 30 ----> (1).
From (1) we get A need 30 Days and B need 90 days
Now take lcm of (A day and B-day).
That is LCM of (30 & 90).
A & B need to complete 90 work.
So, the efficiency of A is (3 w/d) & B's efficiency (1w/d).
When they together (A+B) = work done is (4w/d).
So (90w/(4w/d)) = 22 1/2.
We know that A capability to do work is 3 times of B,ok
Then the the ratio of Efficiency is A:B=3:1
And the ratio of time (days) is A:B=1:3 ...(The ratio get reverse because Efficiency and time are inversely proportional)
Now,
Time taken by A to complete work = (X) day &
Time taken by B to complete work = (X+60) day.
*We compare the ratio of time
(X/X+60)=(1/3) get X = 30 ----> (1).
From (1) we get A need 30 Days and B need 90 days
Now take lcm of (A day and B-day).
That is LCM of (30 & 90).
A & B need to complete 90 work.
So, the efficiency of A is (3 w/d) & B's efficiency (1w/d).
When they together (A+B) = work done is (4w/d).
So (90w/(4w/d)) = 22 1/2.
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