Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
283 comments Page 22 of 29.
Pramod patel said:
8 years ago
I think the best and universal approach is this:
A can do the work in X days, B takes X+60 days for same work,
But (X+60)/X=3/1 as time taken by A and B is in 1:3 ratio,
Solving we get X=30,
A's one day work is 1/30,
B's one day work is 1/90,
combining their one day work we get 1/30+1/90=2/45,
total time taken by them is 45/2.
A can do the work in X days, B takes X+60 days for same work,
But (X+60)/X=3/1 as time taken by A and B is in 1:3 ratio,
Solving we get X=30,
A's one day work is 1/30,
B's one day work is 1/90,
combining their one day work we get 1/30+1/90=2/45,
total time taken by them is 45/2.
Haritha said:
8 years ago
It's a clear explanation.
Thank you @Sheetal.
Thank you @Sheetal.
Tiya said:
8 years ago
Please solve this question.
If the ratio of work efficiency of A and B is 3:2. If A and B together finish a work in 5 days in how much days B alone complete the work?
If the ratio of work efficiency of A and B is 3:2. If A and B together finish a work in 5 days in how much days B alone complete the work?
Bismi maria jose said:
8 years ago
It is said A is 3 time as good as B.
ie. A=3*B
Again given,
A is able to finish a job in 60 days less than B.
say, B takes x days to complete 1 work
therefore A takes x-60 days to complete 1 work(same work)
A's 1 day work=1/x-60
B's 1 day work=1/x.
Substituting;
Applying in formula,
A=3B
ie. 1/x-60=3/x
so,x=90
x-60=30
so we got the number of days A alone and B alone worked i.e 60 and 90
1 day work of (A+B)=1 / 60 + 1 / 90 = 2/45,
So,nobr of days (A+B) worked = 45/2,
Answer is option B.
ie. A=3*B
Again given,
A is able to finish a job in 60 days less than B.
say, B takes x days to complete 1 work
therefore A takes x-60 days to complete 1 work(same work)
A's 1 day work=1/x-60
B's 1 day work=1/x.
Substituting;
Applying in formula,
A=3B
ie. 1/x-60=3/x
so,x=90
x-60=30
so we got the number of days A alone and B alone worked i.e 60 and 90
1 day work of (A+B)=1 / 60 + 1 / 90 = 2/45,
So,nobr of days (A+B) worked = 45/2,
Answer is option B.
Purusottam said:
8 years ago
Yes, correct @Sugumaran.
Purusottam said:
8 years ago
The answer must be 45 days.
Let B does the work in x days.
Now let's think about A's efficiency.
As far as the question is concerned,
3*100/x =100/60.
So, x=180,
Efficiency of A+B=100/60+100/180,
= 20/9%.
So 20/9...........1
1..............9/20
100..........9/20*100 .
=45.
Let B does the work in x days.
Now let's think about A's efficiency.
As far as the question is concerned,
3*100/x =100/60.
So, x=180,
Efficiency of A+B=100/60+100/180,
= 20/9%.
So 20/9...........1
1..............9/20
100..........9/20*100 .
=45.
Anupam Kumar said:
8 years ago
Let us understand this in a much simpler way.
Let the time taken by B to finish the work be X days.
Then according to the question Time is taken by the A is (X-60).
Work done by B in one day is (1/X),
Work done by A in one day is (1/X-60),
And we know that A is three times faster than B, So work done by A in one day is three times the work done by B in one day.
So 3*(1/X)=(1/X-60), 3X-180=X, X=90, Therefore B takes 90 days to complete the work hence A take 30 days to complete the work, therefore together they take 1/(1/30+1/90) days, which is equal to 45/2.
Thank you all.
Let the time taken by B to finish the work be X days.
Then according to the question Time is taken by the A is (X-60).
Work done by B in one day is (1/X),
Work done by A in one day is (1/X-60),
And we know that A is three times faster than B, So work done by A in one day is three times the work done by B in one day.
So 3*(1/X)=(1/X-60), 3X-180=X, X=90, Therefore B takes 90 days to complete the work hence A take 30 days to complete the work, therefore together they take 1/(1/30+1/90) days, which is equal to 45/2.
Thank you all.
Saikrishna said:
8 years ago
a b
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
Rohi said:
8 years ago
Ratio of times taken by A and B = 1:3.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Jack said:
8 years ago
Can anyone explain me why the step 3/2*60 used. I couldn't get the logic of finding difference as 2.
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A and B together can do the work in