Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
30 | 90 | 90 | 45 |
![]() |
45 | = 22 | 1 | days. |
2 | 2 |
Discussion:
281 comments Page 22 of 29.
Bismi maria jose said:
8 years ago
It is said A is 3 time as good as B.
ie. A=3*B
Again given,
A is able to finish a job in 60 days less than B.
say, B takes x days to complete 1 work
therefore A takes x-60 days to complete 1 work(same work)
A's 1 day work=1/x-60
B's 1 day work=1/x.
Substituting;
Applying in formula,
A=3B
ie. 1/x-60=3/x
so,x=90
x-60=30
so we got the number of days A alone and B alone worked i.e 60 and 90
1 day work of (A+B)=1 / 60 + 1 / 90 = 2/45,
So,nobr of days (A+B) worked = 45/2,
Answer is option B.
ie. A=3*B
Again given,
A is able to finish a job in 60 days less than B.
say, B takes x days to complete 1 work
therefore A takes x-60 days to complete 1 work(same work)
A's 1 day work=1/x-60
B's 1 day work=1/x.
Substituting;
Applying in formula,
A=3B
ie. 1/x-60=3/x
so,x=90
x-60=30
so we got the number of days A alone and B alone worked i.e 60 and 90
1 day work of (A+B)=1 / 60 + 1 / 90 = 2/45,
So,nobr of days (A+B) worked = 45/2,
Answer is option B.
Purusottam said:
8 years ago
Yes, correct @Sugumaran.
Purusottam said:
8 years ago
The answer must be 45 days.
Let B does the work in x days.
Now let's think about A's efficiency.
As far as the question is concerned,
3*100/x =100/60.
So, x=180,
Efficiency of A+B=100/60+100/180,
= 20/9%.
So 20/9...........1
1..............9/20
100..........9/20*100 .
=45.
Let B does the work in x days.
Now let's think about A's efficiency.
As far as the question is concerned,
3*100/x =100/60.
So, x=180,
Efficiency of A+B=100/60+100/180,
= 20/9%.
So 20/9...........1
1..............9/20
100..........9/20*100 .
=45.
Anupam Kumar said:
8 years ago
Let us understand this in a much simpler way.
Let the time taken by B to finish the work be X days.
Then according to the question Time is taken by the A is (X-60).
Work done by B in one day is (1/X),
Work done by A in one day is (1/X-60),
And we know that A is three times faster than B, So work done by A in one day is three times the work done by B in one day.
So 3*(1/X)=(1/X-60), 3X-180=X, X=90, Therefore B takes 90 days to complete the work hence A take 30 days to complete the work, therefore together they take 1/(1/30+1/90) days, which is equal to 45/2.
Thank you all.
Let the time taken by B to finish the work be X days.
Then according to the question Time is taken by the A is (X-60).
Work done by B in one day is (1/X),
Work done by A in one day is (1/X-60),
And we know that A is three times faster than B, So work done by A in one day is three times the work done by B in one day.
So 3*(1/X)=(1/X-60), 3X-180=X, X=90, Therefore B takes 90 days to complete the work hence A take 30 days to complete the work, therefore together they take 1/(1/30+1/90) days, which is equal to 45/2.
Thank you all.
Saikrishna said:
8 years ago
a b
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
Rohi said:
8 years ago
Ratio of times taken by A and B = 1:3.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Means B will take 3 times which A will do in 1 time.
If difference of time is 2 days, B takes 3 days,
If the difference of time is 10 days, B takes (3/2) * 10 =15 days.
Jack said:
8 years ago
Can anyone explain me why the step 3/2*60 used. I couldn't get the logic of finding difference as 2.
Shaman said:
8 years ago
Please provide the solution of if A is 5 times better than B together they complete the work in 50 min then B alone can do the work in how many minutes.
Biplab sarkar said:
8 years ago
Here given k=3, n=60.
So formula is -> kn/ (k^2-1) =3*60/ (3^2-1) =180/8=22 1/2 days.
So formula is -> kn/ (k^2-1) =3*60/ (3^2-1) =180/8=22 1/2 days.
Pramod nepal said:
8 years ago
Let see @Shaman.
A finish work in x day and B can 5x day. Then we can do A+B= 1/x +1/5x.
We have A+B = 50,
50 = 5x/6 after sol x= 60 it means A can do in 60 min and B 300 min.
A finish work in x day and B can 5x day. Then we can do A+B= 1/x +1/5x.
We have A+B = 50,
50 = 5x/6 after sol x= 60 it means A can do in 60 min and B 300 min.
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