Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
281 comments Page 23 of 29.
Nik said:
8 years ago
How 4/90 comes?
Rizwan said:
8 years ago
From where does this 4/90 comes? How 4?
Vishal said:
8 years ago
I have better solution.
A:B-3:1(rate).
A:B-1:3(days).
Diff of 2 between ratio of days which is equivalent to 60 and 2*30=60.
Hence 30 will be multiplied to 1 and 3.
And we get 30 and 90.
Together days taken= 30 * 90/30 + 90 = 22 1/2.
A:B-3:1(rate).
A:B-1:3(days).
Diff of 2 between ratio of days which is equivalent to 60 and 2*30=60.
Hence 30 will be multiplied to 1 and 3.
And we get 30 and 90.
Together days taken= 30 * 90/30 + 90 = 22 1/2.
Dusu opo said:
8 years ago
Why 60 days? Please explain.
Sherin said:
8 years ago
Thank you @Showry.
Jiban said:
8 years ago
Can it be in this way?
B will take 180 days more than A. Then calculate for 1 day.
Can anyone solve this?
B will take 180 days more than A. Then calculate for 1 day.
Can anyone solve this?
Nurun Nobi Khokon said:
7 years ago
Let A take x days
So, B takes x+60 days
3x = x+60 (B took 3 times more, so to make the equation equal he have to multiply the days taken by A by 3).
or, 2x = 60,
or, x = 30 days.
A takes 30 days and b takes 30+60 or 90 days.,
Now, (A+B)'s 1 day's work = (1/30+1/90) or 4/90 or 2/45,
So, total days required to do the whole work, 45/2 or 22.5 days.
So, B takes x+60 days
3x = x+60 (B took 3 times more, so to make the equation equal he have to multiply the days taken by A by 3).
or, 2x = 60,
or, x = 30 days.
A takes 30 days and b takes 30+60 or 90 days.,
Now, (A+B)'s 1 day's work = (1/30+1/90) or 4/90 or 2/45,
So, total days required to do the whole work, 45/2 or 22.5 days.
Kavitalodhi said:
7 years ago
In the question clearly, say that A takes 60 days less than B.
So A can do the work in B-60 days,
And time ratio of A:B = 1:3,
1/3=B-x/B =>B=90,A=30.
So, A and B can do the work together 1/30+1/90 =>2/45,
Mix fraction of 2/45 is 22 1/2.
So A can do the work in B-60 days,
And time ratio of A:B = 1:3,
1/3=B-x/B =>B=90,A=30.
So, A and B can do the work together 1/30+1/90 =>2/45,
Mix fraction of 2/45 is 22 1/2.
Mohit said:
7 years ago
3 x 60/3^2-1 = 22 1/2.
Balaji said:
7 years ago
Capacities of A:B=3:1.
Time taken ratio of A:B=1:3.
Difference of ratio in time is 2 = 60 days => A takes 30 days and B takes 90 days => 90/4=22 1/2.
Time taken ratio of A:B=1:3.
Difference of ratio in time is 2 = 60 days => A takes 30 days and B takes 90 days => 90/4=22 1/2.
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