Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
283 comments Page 21 of 29.
JPV said:
9 years ago
Ratio of no days taken to do work by and b= x : 3x.
It's give that diff= 60.
ie 3x-x = 60,
ie x = 30.
No of days taken by B=90.
No of days taken by A=30.
ie total no of days taken when work is done together= 1/30 +1/60,
= 22 1/2.
It's give that diff= 60.
ie 3x-x = 60,
ie x = 30.
No of days taken by B=90.
No of days taken by A=30.
ie total no of days taken when work is done together= 1/30 +1/60,
= 22 1/2.
Sahil Husain said:
9 years ago
A=3B ----------(1)
A-60=B----------(2) from equation 1 & 2
3B-60 = B
B=30 and A = 90
(A+B)'S 1 day work =1\90+1\30 = 2\45,
So (A+B)'s work = 45\2 = 22 1\2.
A-60=B----------(2) from equation 1 & 2
3B-60 = B
B=30 and A = 90
(A+B)'S 1 day work =1\90+1\30 = 2\45,
So (A+B)'s work = 45\2 = 22 1\2.
Dipak said:
9 years ago
Guys. I'm giving simple approach.
3x - x = 60
x = 30
So respective days are 90 and 30.
Total days together = 30 * 90/120 = 22.5.
3x - x = 60
x = 30
So respective days are 90 and 30.
Total days together = 30 * 90/120 = 22.5.
Dhruv said:
9 years ago
Hi, According to me, the solution is;
A= 3B + 60,
So ,
A + B = 0
3B + 60 + B = 0
B = -15.
How to get the correct answer? Please, anyone explain me.
A= 3B + 60,
So ,
A + B = 0
3B + 60 + B = 0
B = -15.
How to get the correct answer? Please, anyone explain me.
Sambhav said:
8 years ago
Hi guys.
It is given that A is thrice efficient then B then the efficiency of A is 3x and that of Y is x. then no of days are For A is(60-y) and for B is y. Then total work done is constant then
3x*(60-y) = x * y.
Then y = 45.
Then total work done by A is 45 X.
And rate of work of A and B will be 3x and x and if they work together the rate will be 4X.
So no of days will be = 45/4.
It is given that A is thrice efficient then B then the efficiency of A is 3x and that of Y is x. then no of days are For A is(60-y) and for B is y. Then total work done is constant then
3x*(60-y) = x * y.
Then y = 45.
Then total work done by A is 45 X.
And rate of work of A and B will be 3x and x and if they work together the rate will be 4X.
So no of days will be = 45/4.
Sasikumar said:
8 years ago
Thanks @Deepti.
Esrak Ahmed Kafi said:
8 years ago
Let B can do it in 3x days.
So, A can do it in X days.
According to Question,
3x-x = 60.
So, X = 30.
So, A can do it 30 days while B can do it in 90 days.
Now in (1/30+1/90) days A & B can together do the work.
=45/2 = 22.5 days.
So, A can do it in X days.
According to Question,
3x-x = 60.
So, X = 30.
So, A can do it 30 days while B can do it in 90 days.
Now in (1/30+1/90) days A & B can together do the work.
=45/2 = 22.5 days.
Rakesh said:
8 years ago
How 3/2? Explain.
Sumanth said:
8 years ago
Thanks for your explanation @Indhu.
Nagesh said:
8 years ago
Thank you for all the given explanation.
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