Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
288 comments Page 2 of 29.
Raseswari said:
12 months ago
I am not understanding this question.
Anyone help me to get it be explaining it along with the formulas?
Anyone help me to get it be explaining it along with the formulas?
(22)
Nikita raisadhar said:
1 year ago
3x - x=60
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
(74)
Subhranil Mondal said:
1 year ago
Assume B can do it in x days.
So A can in x/3 days.
x - x/3 = 60.
then x = 90.
So B can do the work in 90 days.
A can do it in 90/3 = 30 days.
A and B together can do it in 90 * 30/90 + 30 = 22.5 (Ans).
So A can in x/3 days.
x - x/3 = 60.
then x = 90.
So B can do the work in 90 days.
A can do it in 90/3 = 30 days.
A and B together can do it in 90 * 30/90 + 30 = 22.5 (Ans).
(26)
Taukir said:
2 years ago
A takes time = x days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
(87)
Furquan Shiekh said:
2 years ago
Suppose A takes x days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
(76)
Abhirup Paul said:
2 years ago
A is thrice as good as workman as B and therefore can finish a job in 60 days less than B. Working together, they can do it in:
A = 3x, B= 1x ----> {1}
Here A's efficiency = 3.
B's efficiency = 1.
The Sum of their efficiency is 4 (we will need this later on).
According to the question:
A = 3x - 60.
Therefore 1 day's work of A and B is:
1/(3x-60) = 1/(x).
By solving we get x = 30
By putting the value of x in eqn {1}
We get A= 3 X 30 = 90 days.
B = 30 days.
By working together, they can do it in:
90/4 days.
By further solving, we get 22 1/2 days.
A = 3x, B= 1x ----> {1}
Here A's efficiency = 3.
B's efficiency = 1.
The Sum of their efficiency is 4 (we will need this later on).
According to the question:
A = 3x - 60.
Therefore 1 day's work of A and B is:
1/(3x-60) = 1/(x).
By solving we get x = 30
By putting the value of x in eqn {1}
We get A= 3 X 30 = 90 days.
B = 30 days.
By working together, they can do it in:
90/4 days.
By further solving, we get 22 1/2 days.
(27)
Logesh said:
2 years ago
Finding the days for B and A:
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
The ratio difference is 2 and the day difference is 60.
So, for every single inc in ratio, it will increase by 30 days.
From this, we can say that A is 30 days and B is 90 days (1:3 time ratio).
(10)
Vpk said:
2 years ago
A B
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(x-60) x
B=3A;
x = 3(x-60);
x = 3x - 180;
2x = 180;
x = 90;
B = 90 days
A = 30 days.
Work done in 1 day A and B together => 1/30 + 1/90=2/45;
Whole work is will be done 45/2=>22 1/2;
(104)
D venkat raman said:
2 years ago
A is thrice as good as workman as B and therefore can finish a job in 60 days - question
Just think A thrice is 90;
How means;
A is thrice as b;
For A assume as x;
then B assume as 2x;
then C assume as 3x;
in question they thrice -- so we can assume thrice as 3x;
if one is 30 means.
then twice as 60.
then thrice as 90.
So , one day of the work is 1/30, then thrice day of the work is 1/90.
Working together A+B;
1/30+1/90;then.
Then take lcm it will give 90.
Then check whether the 90 is in a and b
3+1/90;
4/90;
2/45;
Then reciprocal it or div it will give 22 1/2.
Just think A thrice is 90;
How means;
A is thrice as b;
For A assume as x;
then B assume as 2x;
then C assume as 3x;
in question they thrice -- so we can assume thrice as 3x;
if one is 30 means.
then twice as 60.
then thrice as 90.
So , one day of the work is 1/30, then thrice day of the work is 1/90.
Working together A+B;
1/30+1/90;then.
Then take lcm it will give 90.
Then check whether the 90 is in a and b
3+1/90;
4/90;
2/45;
Then reciprocal it or div it will give 22 1/2.
(20)
Suhas Wankhede said:
2 years ago
Given Equation
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
A = 3B ---> (i)
Let B=x days --> (ii)
Given:
A = x - 60 days ---> (iii)
Compare i and iii;
x-60 = 3B (i.e B=x).
x-60 = 3x,
x = 30.
A = 3 * 30 = 90 days.
B = 30 days.
LCM 90.
A's Efficiency 1.
b's Efficiency 3.
90/3+1 = 22 1/2 days.
(64)
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A and B together can do the work in