Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
293 comments Page 2 of 30.
Lalith kumar said:
1 year ago
First, A is thrice as good as B means.
If a takes a day to complete work, then b takes 3 days to complete the same work.
Here, time is inversely proportional to work.
So if b takes time T to complete, then a takes T/3 to complete.
In question, they mentioned that the time diff is 60 days.
So, T - T/3 = 60.
2T/3 = 60.
T = 90.
Now, calculate the combined work and how many days it will take.
1/30 + 1/90 = 2/45 = 22.5.
If a takes a day to complete work, then b takes 3 days to complete the same work.
Here, time is inversely proportional to work.
So if b takes time T to complete, then a takes T/3 to complete.
In question, they mentioned that the time diff is 60 days.
So, T - T/3 = 60.
2T/3 = 60.
T = 90.
Now, calculate the combined work and how many days it will take.
1/30 + 1/90 = 2/45 = 22.5.
(25)
Mishra said:
1 year ago
Given: A takes 60 days less than B.
So, let A takes 90days,
B takes 30days.
LCM of 90, 30 = 180 and effeciency of A = 2 (180/90), B = 6 (180/30);
Both work together A + B = (2+6) = 8;
So, total work = 180(LCM);
total days = work/efficiency of both.
= 180/8 = 22.5.
So, let A takes 90days,
B takes 30days.
LCM of 90, 30 = 180 and effeciency of A = 2 (180/90), B = 6 (180/30);
Both work together A + B = (2+6) = 8;
So, total work = 180(LCM);
total days = work/efficiency of both.
= 180/8 = 22.5.
(17)
Yash Sangle said:
1 year ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
so, B = 90, A = 30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
As work done and time are inversely related,
so, B = 90, A = 30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
(13)
Yash Sangle said:
1 year ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
So, B=90, A=30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
As work done and time are inversely related,
So, B=90, A=30.
(1/90 + 1/30) = (2/45),
So, 22 1/5.
(5)
Nallapu Rishith Reddy said:
1 year ago
3/1 = (B)/(B-60).
As work done and time are inversely related,
so, B=90, A=30.
(1/90+1/30)=(2/45),
So, 22 1/5.
As work done and time are inversely related,
so, B=90, A=30.
(1/90+1/30)=(2/45),
So, 22 1/5.
(5)
Raseswari said:
1 year ago
I am not understanding this question.
Anyone help me to get it be explaining it along with the formulas?
Anyone help me to get it be explaining it along with the formulas?
(23)
Nikita raisadhar said:
2 years ago
3x - x=60
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
2x = 60
x = 30
B = 3x = 3 x 30 = 90.
A+B = 1/30 + 1/90,
= 3 + 1/90,
= 4/90,
= 2/42,
= 45/2,
= 22 1/2.
(74)
Subhranil Mondal said:
2 years ago
Assume B can do it in x days.
So A can in x/3 days.
x - x/3 = 60.
then x = 90.
So B can do the work in 90 days.
A can do it in 90/3 = 30 days.
A and B together can do it in 90 * 30/90 + 30 = 22.5 (Ans).
So A can in x/3 days.
x - x/3 = 60.
then x = 90.
So B can do the work in 90 days.
A can do it in 90/3 = 30 days.
A and B together can do it in 90 * 30/90 + 30 = 22.5 (Ans).
(26)
Taukir said:
2 years ago
A takes time = x days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
So, B takes time = 3x days
Now, 3x - x = 60 days
X = 30
3x = 90
1/30 + 1/90 = 1/20 (working together in 1 day).
So, They can do the whole work in 20 days.
(87)
Furquan Shiekh said:
2 years ago
Suppose A takes x days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
Therefore, B will take 3x days.
Now, x = 3x- 60.
x= 30 days.
Thus A takes 30 days and B takes 90 days.
Therefore work done by both in 1 day will be (1/30 + 1/90) = 4/90.
Therefore they take (90/4) = 22.5 days to complete the work.
(77)
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