Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
287 comments Page 15 of 29.
HARINI said:
4 years ago
Given;
A = 3B;
A = B - 60.
Substitute A = 3B in 2nd equation(a=b-60).
3B = B-60
B = 30.
Therefore; A = 3B = 90.
A+B = (1/30 + 1/90) = 2/45.
So, the answer is 22(1/2).
A = 3B;
A = B - 60.
Substitute A = 3B in 2nd equation(a=b-60).
3B = B-60
B = 30.
Therefore; A = 3B = 90.
A+B = (1/30 + 1/90) = 2/45.
So, the answer is 22(1/2).
(24)
Tiya said:
9 years ago
Please solve this question.
If the ratio of work efficiency of A and B is 3:2. If A and B together finish a work in 5 days in how much days B alone complete the work?
If the ratio of work efficiency of A and B is 3:2. If A and B together finish a work in 5 days in how much days B alone complete the work?
Baskar said:
2 decades ago
@bharathi
i think u r in confusion..
just know dat
work = day..
1 day = 2/45 works..
in ques ask abt "work"?
den cross mul
1 work = 45/2 days..
now u got it
i think u r in confusion..
just know dat
work = day..
1 day = 2/45 works..
in ques ask abt "work"?
den cross mul
1 work = 45/2 days..
now u got it
Ranjana shree said:
5 years ago
We can simplify it.
Assume if B worked for 90 days and;
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A + B = 4/90 work.
ie, 90/4 = 22.5.
Assume if B worked for 90 days and;
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A + B = 4/90 work.
ie, 90/4 = 22.5.
Sugumaran said:
2 decades ago
Ratio of time taken=1:3
A finish the work in 60 days and B in x days.
1:3::60:x
x=180 days
So,
A and B 1'days work 1/60+1/180=45 days
Is it correct or not?
A finish the work in 60 days and B in x days.
1:3::60:x
x=180 days
So,
A and B 1'days work 1/60+1/180=45 days
Is it correct or not?
M.Atul said:
2 decades ago
@Sugumaran please read carrefully problem. Though you have got same answer but it doesn't satisfied second condition that differnce in day should be 60 not 120.
Mukunda saini said:
1 decade ago
A is thrice as good as B. So A = 3x and B = x.
A is 60 greater than B. So 3x-x = 60.
2x = 60.
x = 30.
A = 90 and B = 30.
1/90+1/30 = 45/2.
Answer: 22 1/2.
A is 60 greater than B. So 3x-x = 60.
2x = 60.
x = 30.
A = 90 and B = 30.
1/90+1/30 = 45/2.
Answer: 22 1/2.
Neena said:
7 years ago
We can simplify it.
Assume if B worked for 90 days and
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A+B = 4/90 work.
ie, 90/4 = 22.5.
Assume if B worked for 90 days and
C worked for 30 days.
B's 1-day work = 1/90.
A's 1-day work = 1/30.
A+B = 4/90 work.
ie, 90/4 = 22.5.
Bhairus said:
5 years ago
A = 3B;
A time : x-60; B time =x;
In 1 day together work =1/(x-60) +1/x.
And we also know (x-60)/x = 1/3;
From this two got x = 90 and time from eq 1 is 22.5.
A time : x-60; B time =x;
In 1 day together work =1/(x-60) +1/x.
And we also know (x-60)/x = 1/3;
From this two got x = 90 and time from eq 1 is 22.5.
Sridhar said:
1 decade ago
Simple way:
A and B ratio 1:3.
Since A finishes 60 days lesser than be A takes 90 days and B takes 30 days.
So per day calculation (1/90+1/30) = 22.5 days.
A and B ratio 1:3.
Since A finishes 60 days lesser than be A takes 90 days and B takes 30 days.
So per day calculation (1/90+1/30) = 22.5 days.
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A and B together can do the work in