Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
281 comments Page 16 of 29.
SWETHA said:
7 years ago
Since A finishes the job in 60 days less, from (ii) we get: 3X - X = 60.
A=30 B=90,
A+B=1/30+1/90.
=2/45.
A and B together can do the work in 45/2=22 1/2.
A=30 B=90,
A+B=1/30+1/90.
=2/45.
A and B together can do the work in 45/2=22 1/2.
Manohar said:
6 years ago
A+B = 1/60 + 1/180.
A is three times more efficient than B.
(So that if a takes 60 days then B takes 180 days).
And therefore;
2(A+B) = 180/4 = 22 * 1/2.
A is three times more efficient than B.
(So that if a takes 60 days then B takes 180 days).
And therefore;
2(A+B) = 180/4 = 22 * 1/2.
Neeraj said:
1 decade ago
Shortcut:
A & B together will complete in 6/14/8 = 24/7 days = 3 3/7 days.
Work completed in 3 days. So C's share 3/7 days.
Now 3200/24/7*3/7 = 400.
A & B together will complete in 6/14/8 = 24/7 days = 3 3/7 days.
Work completed in 3 days. So C's share 3/7 days.
Now 3200/24/7*3/7 = 400.
BLACK said:
9 years ago
Ratio of time taken by A & B = 1 : 3.
Suppose B takes x days to finish the job.
Then A takes (x-60) days.
So, (x-60) : x = 1:3
x= 90.
So rest are same.
Suppose B takes x days to finish the job.
Then A takes (x-60) days.
So, (x-60) : x = 1:3
x= 90.
So rest are same.
Rajashekar said:
7 years ago
Shortcut of these type of problems:
A&B = Difference * 'n' times / n^2 - 1.
= 60*3/3^2-1
= 180/9-1.
= 180/8=22.5 or 22 1/2.
A&B = Difference * 'n' times / n^2 - 1.
= 60*3/3^2-1
= 180/9-1.
= 180/8=22.5 or 22 1/2.
Rajesh said:
5 years ago
Work=3:1.
Time 1:3.
2 part=60 (difference).
1 part=30.
1*30:3*30=30:90.
He asked work of B( 90)can do by both in how many days.
90/(1+3)= 90/4=22.5 days.
Time 1:3.
2 part=60 (difference).
1 part=30.
1*30:3*30=30:90.
He asked work of B( 90)can do by both in how many days.
90/(1+3)= 90/4=22.5 days.
(1)
ASHIRWAD said:
1 decade ago
HI FRIENDS THIS IS THE simplest method for solving this type of que....
K*S/(A^2-1)
where S=DAYS FOR FINISHING WORK(60 GIVEN IN QUE)
K=3 GIVEN IN QUE
K*S/(A^2-1)
where S=DAYS FOR FINISHING WORK(60 GIVEN IN QUE)
K=3 GIVEN IN QUE
Surya said:
1 decade ago
Simple formula with solution:
(D) n/n2 (i.e n square)-1 = work together.
Details:
D-60, n-3, by putting the formula = (60)3/3's square-1 = 22.5 days.
(D) n/n2 (i.e n square)-1 = work together.
Details:
D-60, n-3, by putting the formula = (60)3/3's square-1 = 22.5 days.
Shaman said:
8 years ago
Please provide the solution of if A is 5 times better than B together they complete the work in 50 min then B alone can do the work in how many minutes.
Dhruv said:
8 years ago
Hi, According to me, the solution is;
A= 3B + 60,
So ,
A + B = 0
3B + 60 + B = 0
B = -15.
How to get the correct answer? Please, anyone explain me.
A= 3B + 60,
So ,
A + B = 0
3B + 60 + B = 0
B = -15.
How to get the correct answer? Please, anyone explain me.
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